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UkoKoshka [18]
3 years ago
9

You are making a picture frame of uniform width for a picture that is to be displayed at the local museum. The picture is 3.25 f

eet tall and 3 feet wide. The museum has allocated 15 square feet of wall space to display the picture. What should the width of the frame be in order to use all the allocated space?
(This is a factoring problem)
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0
x-\ width\ preferred\\\\
Area=width*length\\\\
length=3,25feet\\
Area=15feet^2\\\\
15=3,25*x\ \ \ \ | divide\ by\ 3,25\\\\x=4,61feet\\\\It\ should\ be\ 4,61\ feet \ long.

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The domain of both f(x) = x - 6 and g(x) = x + 6 is all real numbers. What is the domain of h(x) = f(x)/g(x)?
arlik [135]
This is a quotient (division) of two functions we must be concerned with the fact that division by zero is undefined.

Since g(x) is in the divisor position, it cannot equal 0.
x+6 \neq 0
x \neq -6 Subtract 6 from both sides to solve.
So the domain is all real numbers except -6
Set notation {x | x ∈ R, x ≠ -6}
Interval notation (-∞,-6)∪(-6,∞)
6 0
3 years ago
Find an equation of the circle and sketch it if it has: Center on y=4, tangent x-axis at (–2, 0)
Digiron [165]

Answer:

(x+2)^2+(y-4)^2=16

OK, lets start by drawing a basic graph (the first one) so we can visualize.

We already know that the y coordinate of the circle's center is 4.

We know that the circle is tangent to the X axis at (-2,0)

That means the x coordinate of the center has to be -2, as the tangent is a point on the edge of the circle that touches a line at exactly one point.

The radius is the distance from the center of the circle to its edge. We know the center's location now, it is (-2, 4) and a point on the edge of the circle (the tangent point) which is (-2,0). so the distance between the points is 4 which is the radius (you can use the distance formula, but it's quite oblivious.)

We can imagine the circle should look like this (the second one):

Now we can piece together an equation

The equation of a circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius. When we put the numbers in: we get (x-(-2))^2+(y-(4))^2=4^2 which can be simplified into (x+2)^2+(y-4)^2=16 which is the answer.

Step-by-step explanation:

4 0
3 years ago
Suppose we want to build a rectangular storage container with open top whose volume is $$12 cubic meters. Assume that the cost o
Snezhnost [94]

Answer:265.25

Step-by-step explanation:

Given

Volume of box=12 m^3

height is 3 times the width

let height, length and breadth be H, L & B

H=3\times B

V=12=L\times B\times H

4=B^2\times L[/tex]

L=\frac{4}{B^2}

Cost of side walls $ 8/m^2

Cost of base $ 12/m^2

Cost of side walls=(2LH+2BH)\cdot 8

Cost of base =12LB

Total cost C=16LH+16BH+12LB

C=48LB+48B^2+12LB

C=\frac{192}{B}+48B^2+\frac{48}{B}

differentiate C w.r.t B to get minimum cost

\frac{\mathrm{d} C}{\mathrm{d} B}=-\frac{192}{B^2}+2\times 48 B-\frac{48}{B^2}

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H=3\times 1.35=4.07 m

L=2.19 m

C=$ 265.25

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