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Greeley [361]
3 years ago
15

Solve y = x - 5 if the domain is -3

Mathematics
1 answer:
DedPeter [7]3 years ago
6 0

Answer:

y = -8

Step-by-step explanation:

The domain is the x values so x=-3

y = x-5

Substituting x=-3

y = -3-5

y=-8

You might be interested in
What is the value of the expression 29-|7-11|
Makovka662 [10]

The value of 29 - |7 - 11| = 25

We have the following expression -

29 - |7 - 11|

We have to find its value.

<h3>Find the value of the expression -</h3><h3>X + | \piY |    where Y < 0</h3>

We have -

X + | \piY |

Since Y < 0 - therefore \piY < 0

Now -

|a| = - a   { for a < 0}

Therefore -

X -  \piY

According to the question, we have -

29 - |7 - 11|

29 - | -4 |

29 - 4

25

Hence, the value of 29 - |7 - 11| = 25

To learn more about Modulus function, visit the link below-

brainly.com/question/13103168

#SPJ2

7 0
2 years ago
Read 2 more answers
5x + y =7<br> 20x + 2 = y
kodGreya [7K]

Answer:

y = 6

x = 0.2

Step-by-step explanation:

5x + y =7

20x + 2 = y

5x(4) + y(4) = 7(4)

20x + 4y = 28

(20x = 28 - 4y) = (20x = y - 2)

28 - 4y = y - 2

30 - 4y = y

30 = 5y

y = 6

5x + y =7

20x + 2 = y

y = 7 - 5x

7 - 5x = 20x + 2

5 - 5x = 20x

5 = 25x

x = 0.2

4 0
3 years ago
What does 9740399 round to by the nearest hundred thousand?
weeeeeb [17]
1,000,000 because since it is 100,000 the closest number is 1,000,000
7 0
3 years ago
What facts are required in order to conclude that m∠ADE = m∠ABC?
mariarad [96]

Answer:

The correct option is;

DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)

Step-by-step explanation:

Given that we have;

1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC

2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC

3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC

Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;

AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))

∴ (sin(m∠ADE)) = (sin(m∠ABC))

m∠ADE) = m∠ABC).

3 0
3 years ago
during the 2011 season, a quarterback passed for 302 yards per game. he played in all 16 regular season games that year. how man
MariettaO [177]
302 times 16 because he passed 302 yards for every game 4832
7 0
3 years ago
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