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dangina [55]
3 years ago
10

A car rental costs $50 for the first day. Additional days cost $35 per day, unless the car is rented for 7 days or more, in whic

h case there is a 10% discount on the daily rate. Identify the expression which represents the cost of renting a car if the car has been rented for more than a week.
A.) 45+35x
B.) 45+31.5x
C.) 50+35x
D.) 50+31.5x
Mathematics
2 answers:
Elan Coil [88]3 years ago
4 0
The answer is D,I think it's help
Anni [7]3 years ago
3 0

Answer:

Option D \$50+\$31.5x

Step-by-step explanation:

Let

x------> the number of days

y----> the cost of renting a car

we know that

For x

y=\$50+\$35x

For x\geq 7\ days

The rate is equal to

0.90*\$35=\$31.5

so

y=\$50+\$31.5x

In this problem. the car has been rented for more than a week

therefore

x> 7\ days

The cost of renting a car is equal to

y=\$50+\$31.5x


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15 point question
Natalka [10]

Answer:

It will cost $12.5 per person to charter a bus for 36 passengers

Step-by-step explanation:

The cost per person c of chartering a tour bus  varies inversely as the number of passengers  n.

We can write:

c\:\alpha \:\frac{1}{n} \\c=\frac{k}{n}

where k is constant of proportionality

We are given when c = 22.50, n = 20

We need to find c when n = 36

First using c = 22.50, n = 20 we will find k, the constant of proportionality

c=\frac{k}{n}\\22.50=\frac{k}{20}\\k=22.50 \times 20\\k=450

So, we get k = 450

Now, we will find c when n = 36

c=\frac{k}{n}\\c=\frac{450}{36}\\c=12.5

So, we get the value of c: c = 12.5

Therefore, It will cost $12.5 per person to charter a bus for 36 passengers

8 0
3 years ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
Consider U = {x\x is a real number}
zysi [14]

Answer:

The fourth pair of statement is true.

9∈A, and 9∈B.

Step-by-step explanation:

Given that,

U={x|  x is real number}

A={x| x∈ U and x+2>10}

B={x| x∈ U and 2x>10}

  • 5 ∈ A , 5 ∈ B

If 5∈ A, Then it will be satisfies x+2>10 , but 5+2<10.

Similarly, If 5∈ B, Then it will be satisfies 2x>10 , but 2.5=10.

So, 5∉A, and 5∉B.

  • 6 ∈ A , 6 ∈ B

If 6∈ A, Then it will be satisfies x+2>10 , but 6+2<10.

Similarly, If 6∈ B, Then it will be satisfies 2x>10 , and 2.6=12>10.

So, 6∉A, and 6∈B.

  • 8 ∈ A , 8 ∈ B

If 8∈ A, Then it will be satisfies x+2>10 , but 8+2=10.

Similarly, If 8∈ B, Then it will be satisfies 2x>10.  2.8=16>10.

So, 8∉A, and 8∈B.

  • 9 ∈ A , 9 ∈ B

If 9∈ A, Then it will be satisfies x+2>10 , but 9+2=11>10.

Similarly, If 9∈ B, Then it will be satisfies 2x>10.  2.9=18>10.

So, 9∈A, and 9∈B.

3 0
2 years ago
Estimate the perimeter and the area of the shaded figure to the nearest whole number.
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

The area and perimeter of the given shaded figure are respectively 33.12 unit² and 20.56 units.

Area and perimeter-based problem:

What information do we have?

Radius of semi-circle = 8 / 2 = 4 unit

Length of remain Rectangle = 8 unit

Width of remain Rectangle = 2 unit

Perimeter of shaded figure = πr + (l + 2b)

Perimeter of shaded figure = (3.14)(4) + [4 + (2)(2)]

Perimeter of shaded figure = 12.56 + 4 + 4

Perimeter of shaded figure = 20.56 units

Area of shaded figure = πr²/2 + lb/2

Area of shaded figure = (3.14)(4)²/2 + (8)(2)/2

Area of shaded figure = (3.14)(8) + 8

Area of shaded figure = 25.12 + 8

Area of shaded figure = 33.12 unit²

5 0
2 years ago
Read 2 more answers
A, B and C lie on a straight line.
horsena [70]
Here you go, i added a bit of explanation as to why i used the numbers to help you understand the method :)

6 0
2 years ago
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