Solution:
We have been asked to find the distance between the points (3, 3) and (7, 3).
we can find the distance between the two points using the distance formula.
The distance formula is given as

Now substitute the given values we get

Hence the distance between the given points is 4
Looking at the choices i believe you need a g in your question. If it is 4g+2
Then you factor out at 2 to get 2(2g+1) choice a
If it 4+2g then you also factor out a 2 but this time get 2(2+g) choice b
Depending on what the question actually is those would be the answers
Answer:
133.33 mph
Step-by-step explanation:
The small trick is to notice the time. Is it 8:00 AM the same day. We don't know, but we will assume it is.
So the truck was on the road for 2 hours.
The car was on the road for 2 - 1/2 = 1 1/2 = 1.5 hours.
The distance travelled was 200 miles
Solution
d = r * t
200 = r * 1.5
200/1.5 = r
r = 133.33 miles / hour
The noise you hear is a siren trying to catch up to the car.
Answer:
Part A:
For number 1, the bus drives non-linear. It is not a constant rate but it is increasing.
For number 2, the bus is at a stopping point.
For number 3, the bus drives in a non-linear rate but it still increasing.
For number 4, the bus is at its last stop, the middle of the bus ride, the peak of the time.
For number 5, the bus comes to a non-linear decrease in the route. and eventually the end.
Part B:
The bus is increasing in numbers 1 and 3, and decreasing for number 5, and at a constant at numbers 2 and 4.
Part C:
The graph is non-linear, as the slope is not at a constant.