Answer: 32 paving stones
Step-by-step explanation:
Hi, to answer this question, first we have to convert the measures of the paving stones into meters.
Since: 1m = 100 cm
50 cm /100 = 0.5m
Now, we have to calculate the area of each paving stone:
Area of a square: s^2 = 0.5^2 = 0.25m2
Next, the area of the path.
Area of a rectangle = width x length = 1 x 8 = 8 m2
Finally, we have to divide the area of the path by the area of each paving stone:
8/0.25 = 32 paving stones
Feel free to ask for more if needed or if you did not understand something.
Step-by-step explanation:
4x-9y=-9 1
2x +3y=3 2
1 - 2(2)
4x -9y=-9
(2)* -4x -6y=6
________
0-15y=-3
15y=3
y=3/15
y=1/5
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Answer:
1.1
Step-by-step explanation:
Write out a long division problem! Since you can't have a decimal in the divisor, multiply both numbers by 10. This will leave you with 39.6÷36. Now all you have to do is follow the steps and end up with an answer of 1.1
Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.
First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.
Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:
1, 3, 5, 7, 9, 11, 13, 15 .
Number of items in the set . . . 8
Sum of all the items in the set . . . 64
Hmmm. That's interesting. 64 happens to be the square of 8 .
Do you think that might be all there is to it ?
Let's check it out:
Even-numbered lists of odd numbers:
1, 3 Items = 2, Sum = 4
1, 3, 5, 7 Items = 4, Sum = 16
1, 3, 5, 7, 9, 11 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .
Amazing ! The sum is always the square of the number of items in the set !
For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.
I slogged through it on my calculator, and it's true.
I never knew this before. It seems to be something valuable
to keep in my tool-box (and cherish always).
