Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.

Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
Answer:
It's graph D
Step-by-step explanation:
No it’s D because it is rise over run and you rise 3 and run 1. 3/1 is simplified to 3.
The distance (r) between any two points (a,b) and (c,d) is :—

Putting the values,



The distance between the points is √41