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Varvara68 [4.7K]
3 years ago
5

Show your work in the comments below and and the answer choice

Mathematics
1 answer:
Olegator [25]3 years ago
4 0

Answer:

Your answer is A.

Step-by-step explanation:

5 x 12 = 60

5 x 6 = 30 / 2 = 15

60 + 15 = 75

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If edging cost $2.32 per 12-inch stone, and you want a double layer of edging around your flower bed that is 6 yards by 1 yard.
aksik [14]
12 inches = 1foot
1yard = 3feet
6yards = 18feet
Rerange the question:
If edging cost $2.32 per 1foot stone, and you want a double layer of edging around your flower bed that is 18feet by 3feet. How much will edging you flower bed cost?
Perimter:
2(18+3)=42
And since you want to double it; double the perimeter too.
42(2)=84

2.32(84)=194.88
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3 years ago
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What is 289% as a decimal
lakkis [162]

Answer:

the answer is 2.89

Step-by-step explanation:

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2 years ago
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An urn contains n white balls andm black balls. (m and n are both positive numbers.) (a) If two balls are drawn without replacem
Genrish500 [490]

DISCLAIMER: Please let me rename b and w the number of black and white balls, for the sake of readability. You can switch the variable names at any time and the ideas won't change a bit!

<h2>(a)</h2>

Case 1: both balls are white.

At the beginning we have b+w balls. We want to pick a white one, so we have a probability of \frac{w}{b+w} of picking a white one.

If this happens, we're left with w-1 white balls and still b black balls, for a total of b+w-1 balls. So, now, the probability of picking a white ball is

\dfrac{w-1}{b+w-1}

The probability of the two events happening one after the other is the product of the probabilities, so you pick two whites with probability

\dfrac{w}{b+w}\cdot \dfrac{w-1}{b+w-1}=\dfrac{w(w-1)}{(b+w)(b+w-1)}

Case 2: both balls are black

The exact same logic leads to a probability of

\dfrac{b}{b+w}\cdot \dfrac{b-1}{b+w-1}=\dfrac{b(b-1)}{(b+w)(b+w-1)}

These two events are mutually exclusive (we either pick two whites or two blacks!), so the total probability of picking two balls of the same colour is

\dfrac{w(w-1)}{(b+w)(b+w-1)}+\dfrac{b(b-1)}{(b+w)(b+w-1)}=\dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

<h2>(b)</h2>

Case 1: both balls are white.

In this case, nothing changes between the two picks. So, you have a probability of \frac{w}{b+w} of picking a white ball with the first pick, and the same probability of picking a white ball with the second pick. Similarly, you have a probability \frac{b}{b+w} of picking a black ball with both picks.

This leads to an overall probability of

\left(\dfrac{w}{b+w}\right)^2+\left(\dfrac{b}{b+w}\right)^2 = \dfrac{w^2+b^2}{(b+w)^2}

Of picking two balls of the same colour.

<h2>(c)</h2>

We want to prove that

\dfrac{w^2+b^2}{(b+w)^2}\geq \dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

Expading all squares and products, this translates to

\dfrac{w^2+b^2}{b^2+2bw+w^2}\geq \dfrac{w^2+b^2-b-w}{b^2+2bw+w^2-b-w}

As you can see, this inequality comes in the form

\dfrac{x}{y}\geq \dfrac{x-k}{y-k}

With x and y greater than k. This inequality is true whenever the numerator is smaller than the denominator:

\dfrac{x}{y}\geq \dfrac{x-k}{y-k} \iff xy-kx \geq xy-ky \iff -kx\geq -ky \iff x\leq y

And this is our case, because in our case we have

  1. x=b^2+w^2
  2. y=b^2+w^2+2bw so, y has an extra piece and it is larger
  3. k=b+w which ensures that k<x (and thus k<y), because b and w are integers, and so b<b^2 and w<w^2

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3 years ago
Mobile users in India have gone up by 20% percent in a year. There are 540 million mobile users today.
DanielleElmas [232]
432 million, 540 times .20 equals 108, subtract 108 from 540 and you get your answer
7 0
2 years ago
Multiply and simplify the product.
lianna [129]
Multiplying complex numbers is a lot like multiplying binomial terms. The only relation one has to remember when dealing with complex numbers is that i² = -1.

Now let us try to multiply binomials. This is done by adding the products of the first term of the first binomial distributed to the second binomial, and the second term of the first binomial distributed to the second binomial. This is done below:

(<span>3 – 5i)(–2 + 4i)  = -6 + 12i + 10i -20i²
</span>
Simplifying and applying i²<span> = -1:</span>
-6 + 22i - 20(-1)
-6 + 22i + 20
14 + 22i

Among the choices, the correct answer is B.
5 0
3 years ago
Read 2 more answers
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