1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
o-na [289]
3 years ago
15

What algebraic expression must be added to the sum of 3x2 +4x+8 and 2x2−6x+3 to give 9x2−2x−5 as the result?

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

4x² - 16 is the algebraic expression that must be added to get the result as 9x²- 2x - 5.

<u>Step-by-step explanation:</u>

The question is asked for the algebraic expression must be added to the sum of 3x²+4x+8 and 2x2−6x+3 to give 9x²- 2x - 5 as the result.

Therefore,

The first step is to find of sum of 3x²+4x+8 and 2x²-6x+3.

To find the sum :

3x²+4x+8

<u>2x²-6x+3 </u>

<u>5x²-2x+11</u>

The sum is 5x²-2x+11.

Now, the second step is to subtract 5x²-2x+11 from the result 9x²- 2x - 5.

  9x²- 2x - 5

- <u>(5x²-2x+11)</u>

  <u> 4x²    -16 </u>

Thus, 4x²-16 is the algebraic expression that must be added with 5x²-2x+11 to get a result of 9x²- 2x - 5.

You might be interested in
Ok guys ik that this isn't a part of academic but i wanna say a story ... since i had 15 subs ive always wanted 100 .. like so b
Contact [7]

I'll sub my guy. Don't give up, keep climbing.

5 0
3 years ago
Given h(x) = -5x + 3, find h(5).
lyudmila [28]
5x+5=3
5x=-2
X=-2/5
Alternative form is x=-0.4
6 0
3 years ago
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
4 years ago
Read 2 more answers
Find ten rational numbers between -1 by 5 and 1 by 2 ​
uysha [10]

Answer:

Step-by-step explanation:

First both the rational numbers should have same denominators. So, find least common denominator

Least common denominator is 10

\frac{-1}{5}=\frac{-1*2}{5*2}=\frac{-2}{10}\\\\\\\frac{1}{2}=\frac{1*5}{2*5}=\frac{5}{10}\\\\\\

Now multiply  the numerator  and denominators of the both the numbers by 10.

\frac{-2*10}{10*10}= \frac{-20}{100} \ and \ \frac{5*10}{10*10}=\frac{50}{100}\\\\\\Now\ 10 \ rational  \ numbers \ between\frac{-20}{10} \ and \ \frac{50}{100} \ is \\\\\\\frac{-19}{100},\frac{-18}{100},\frac{-17}{100},\frac{-16}{100}.\frac{-15}{100},\frac{-14}{100},\frac{-13}{100},\frac{-12}{100},\frac{-11}{100};\frac{-10}{100}

8 0
3 years ago
Pls help! will mark brainliest if correct
nevsk [136]

I dont know what is it sorry but I try the love yaaysya

3 0
3 years ago
Other questions:
  • Helppppppppppppppppppppppppppppppppp
    8·1 answer
  • How can the mean be 3 1/2 people when half a person does not exist
    11·1 answer
  • For health reasons Sarah needs to limit her fat intake to 25% of the total calories consumed in a day if the fat intake is 550 c
    15·2 answers
  • What is the difference between the product of four and a number and 6
    10·2 answers
  • An organization has a monthly budget of x dollars. Every month $2,070 is spent on salaries. One-fourth of the
    6·1 answer
  • A beverage is made by mixing 1 part of water with 3 parts of fruit juice. How many parts of water are mixed with one part of fru
    15·1 answer
  • Whats the answer for x - 35 &gt; 15 Plz help with this i will mark brainliest
    14·2 answers
  • Identify the triangle ​
    11·2 answers
  • 4.) You are a Brusher/Bather in a grooming facility. It's the end of the day and you have to split up all the
    6·1 answer
  • In a P.7 class, 20% of the boys were absent for the Mock Examinations, of the remainder of the boys were present Find the fracti
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!