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musickatia [10]
3 years ago
6

In a certain Algebra 2 class of 25 students, 13 of them play basketball and 11 of them play baseball. There are 4 students who p

lay neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

\frac{4}{5}

Step-by-step explanation:

Given: There are 2 classes of 25 students.

            13 play basketball

            11 play baseball.

            4 play neither of sports.

Lets assume basketball as "a" and baseball as "b".

We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)

As given total number of student is 25

Now, subtituting the values in the formula.

⇒P(a∪b)= \frac{13}{25} +\frac{11}{25} -\frac{4}{25}

taking LCD as 25 to solve.

⇒P(a∪b)= \frac{13\times 1+11\times 1-4\times 1}{25} = \frac{20}{25}

∴ P(a∪b)= \frac{4}{5}

Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is \frac{4}{5}.

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PLEASE HELP WITH NUMBER 11 ASAP!!!! (Please show how you got the answer)
Alex777 [14]

Answer:

Triangle B is right

Step-by-step explanation:

Using the converse theorem of Pythagoras.

If the square of the longest side in a triangle equals the sum of the squares of the other 2 sides then the triangle is right.

Triangle A

longest side squared = 36² = 1296

26² + 18² = 676 + 324 = 1000 ≠ 1296

Hence triangle A is not right

Triangle B

longest side squared = 25² = 625

20² + 15² = 400 + 225 = 625 ← correct

Hence triangle B is right


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3 years ago
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denis-greek [22]
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2 years ago
PLEASE HELP!
ELEN [110]

Answer:

Colin's mean score = 17.10

The new mean is 18.00

Step-by-step explanation:

Given scores: 31, 10, 26, 16, 28, 31, 9, 11, 8, 1

number of terms: 10

mean is calculated by given formula = sum of all the data set/ number of terms in the data set.

mean for the 10 scores = (31+ 10+ 26+ 16+ 28+ 31+ 9+ 11+ 8+ 1 )/10

                                       = 171/10 = 17.1

Colin's mean score = 17.10

____________________________________________

runs scored by Colin in 11th match = 27

number of terms: 11

new mean = new sum /number of terms

new mean = (old sum score + 27)/11 = (171+27)/11

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The new mean is 18.00

3 0
2 years ago
What two numbers add to be 6 and multiply to be 15
yarga [219]
   
\displaystyle \bf \\
x_1+x_2=6\\\\
x_1\cdot x_2=15\\\\
\Longrightarrow~~x^2-6x+15=0\\\\
x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{6\pm\sqrt{36-60}}{2}=\\\\
=\frac{6\pm\sqrt{-24}}{2}=\frac{6\pm2\sqrt{-6} }{2}=3\pm i\sqrt{6}\\\\
x_1=\boxed{3-i\sqrt{6}}\\\\
x_2=\boxed{3+i\sqrt{6}}\\\\
\texttt{Verify:}\\\\
x_1+x_2=3-\underline{i\sqrt{6}}+3+\underline{i\sqrt{6}}=3+3=6~~correct\\\\
x_1\cdot x_2=(3-i\sqrt{6})(3+i\sqrt{6})=3^2-(i\sqrt{6})^2=9+6=15~~correct



4 0
3 years ago
Nathan is collecting aluminum cans for charity. One empty 355 ml can weighs about 17 g. It takes 59 cans to get about 1 kg of 10
Jlenok [28]

Answer:

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Step-by-step explanation:

Each 59 cans are about 1 kg.

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How many times 59 cans did he collect?

1978/59 = 33.5

He collected 1978 cans which is 33.52 times 59 cans, so he collected 33.5 kg

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