Answer:
x=-11\5+13\5i-iy
y=ix+(13\5+11\5i)
Step-by-step explanation:
x+yi=-7+3i\2+i
x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}
x+yi=-11\5+13\5i
x=-11\5+13\5i-yi
x=-11\5+13\5i-iy
x+yi=\frac{-7+3i}{2+i}
x+yi=\frac{\left(-7+3i\right)\left(2-i\right)}{\left(2+i\right)\left(2-i\right)}
x+yi=\frac{-11+13i}{5}
x+yi=-\frac{11}{5}+\frac{13}{5}i
yi=-\frac{11}{5}+\frac{13}{5}i-x
\frac{iy}{i}=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}
y=\frac{-\frac{11}{5}+\frac{13}{5}i-x}{i}
I hope this helps you
1.x^2-8x-3=0
disctirminant =(-8)^2-4.1. (-3)
disctirminant =64+12
disctirminant =76
x1,2= -b(+,-)square root of disctirminant /2a
x1=-(-8)+square root of 76/2.1
x1=8+square root of 76/2
x2=8-square root of 76/2
27 1 27 10
---- x ---- = ---- OR 1 ----
1 17 17 17
