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Reika [66]
3 years ago
15

Hurry i need the answers quick!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
finlep [7]3 years ago
8 0
Hiiiiiiiiiiiiiiiiiiiiiii
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It is a segment that connects two distinct points on a cicrcle.

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Una máquina demora 2 minutos y 30 segundos en fabricar una silla. Si en un día la máquina funciona sin parar 8 horas ¿Cuántas si
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Una máquina demora 2 minutos y 30 segundos en fabricar una silla. Si en un día la máquina funciona sin parar 8 horas ¿Cuántas sillas fabricará?

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3 years ago
Suppose you work in the quality assurance department of a chemical processing plant and it is your responsibility to ascertain w
aleksandrvk [35]

Answer:

48.668 ≤ μ ≤ 63.332

Step-by-step explanation:

Given the data:

Sample (X) : 71, 45, 54, 75, 50, 49, 63, 55, 48, 50

Number of samples (n) = 10

α = 95% = 0.05

Determine the range within which the true mean of the fluid samples from the day shift will be with a 95% confidence

True mean = μ

Confidence interval :

m ± t(α/2 ; df) * s/√n

m - t(α/2 ; df) * s/√n ≤ μ ≤ m + t(α/2 ; df) * s/√n

m = sample mean ; s = sample standard deviation ; df = degree of freedom =(n - 1) = (10 - 1) = 9

Calculating the sample mean and standard deviation using calculator to save computation time :

71, 45, 54, 75, 50, 49, 63, 55, 48, 50

m = 56 ; s = 10.25

m - t(0.05/2 ; 9) * s/√n ≤ μ ≤ m + t(0.05/2 ; df) * s/√n

From t table : t(0.05/2 ; 9) = t(0.025, 9) = 2.262

56-2.262 * (10.25/√10) ≤ μ ≤ 56+2.262 * (10.25/√10)

48.668 ≤ μ ≤ 63.332

6 0
3 years ago
Rewrite in simplest terms: -8(7y-8)-3(7y-7)
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Answer:

−77y+85

I hope I helped!

7 0
2 years ago
Conduct the appropriate hypothesis test and compute the test statistic. A company that produces fishing line undergoes random te
andre [41]

Answer:

Option D) Yes, because the test statistic is -2.01

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 30 pound

Sample mean, \bar{x} = 29.1 pounds

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s =  2 pounds

First, we design the null and the alternate hypothesis

H_{0}: \mu = 30\text{ pounds}\\H_A: \mu < 30\text{ pounds}

We use one-tailed(left) t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{29.1 - 30}{\frac{2}{\sqrt{20}} } = -2.012

Now,

t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = -1.729

Since,                    

t_{stat} < t_{critical}

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis. Thus, there were enough evidence to conclude that the fishing line breaks with an average force of less than 30 pounds.

Option D) Yes, because the test statistic is -2.01

5 0
3 years ago
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