Question

Solve x2 – 8x = 3 by completing the square. which is the solution set of the equation

Answer 1

I hope this helps you 1.x^2-8x-3=0 disctirminant =(-8)^2-4.1. (-3) disctirminant =64+12 disctirminant =76 x1,2= -b(+,-)square root of disctirminant /2a x1=-(-8)+square root of 76/2.1 x1=8+square root of 76/2 x2=8-square root of 76/2

Answer 2

Answer:

$x-4=\sqrt{19}\Rightarrow x= 4+\sqrt{19}\\\\\ x-4=-\sqrt{19}\Rightarrow x= 4-\sqrt{19}$

 is the solution set for the given equation

Step-by-step explanation:

Given : Equation $x^2-8x=3$      

We have to find the solution set for the given equation using   completing the square method.

Consider  the given equation $x^2-8x=3$

Write the given equation in form of $x^2+2ax+a^2=\left(x+a\right)^2$

Comparing , we have,

x = x

2ax = -8x

a = - 4

Adding $a^2=16$ both side, we have,

$x^2-8x+\left(-4\right)^2=3+\left(-4\right)^2$

Simplify, we have,

$\left(x-4\right)^2=19$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

thus,

$(x-4)=\pm\sqrt{19}$

Therefore,

 $x-4=\sqrt{19}\Rightarrow x= 4+\sqrt{19}\\\\\ x-4=-\sqrt{19}\Rightarrow x= 4-\sqrt{19}$

is the solution set for the given equation