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3 years ago

Which relations are functions? Select Function or Not a function for each graph.

Mathematics

2 answers:

PtichkaEL [24]3 years ago

7 0

Answer:

Step-by-step explanation:

the points they give us are 12,90 , 8,60 , and 4,30

myrzilka [38]3 years ago

7 0

Each graph is a function except for graph number 3 , 2 and 1

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Luke’s that seven pieces of wood on top of one another if each piece was 4/8 of a foot tall how tall was his pile

Ludmilka [50]

Answer:

6 1/2 feet or 78 inches tall

Step-by-step explanation:

You have to multiply 4/8 by 7/1

First you multiply the nominators: 4 × 7 = 28

Then you multiply the denominators: 8 × 1 = 8

So the fraction would be 28/8 and it simplifies to 7/2

You can turn it into an improper fraction by seeing how many times 2 will go into seven evenly, which would be 6 times with 1 half left over

Therefore it would be 6 1/2 feet or 78 inches tall

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2 years ago

If x=6 and y=-3 then find (xy)²

aniked [119]

324

Step by step explanation This is how I got the answer to your question and I gave you the solution I hope this helps you out

6 0

2 years ago

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A park has a length to width ratio of 7:4 and the perimeter of the park is 880 meters. What are the length and width of the park

Schach [20]

Step-by-step explanation:

Ratio of length to width = 7 : 4

length = 7x

width = 4x

7x + 4x = 11x

length = 880

$880 + 4x = 11x$

$880 = 11x - 4x$

$880 = 7x$

$\frac{880}{7} = x$

$125.71 = x$

width = 4x

= 4(125.71)

= 502.85

3 0

2 years ago

Both fractions in the expression of 1/3 +1/3 are examples of...

kirza4 [7]

Equivalent fractions

7 0

3 years ago

Find (a) arc length and (b) Area of a sector.

barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

<u>Calculation</u>

Given:

$\theta=\dfrac{5 \pi}{8}$
r = 15 cm

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}$

5 0

1 year ago