Answer:
C
Step-by-step explanation:
cuz itz IRRATIONAL
Answer:
ASA
Step-by-step explanation:
Given:
Two triangles ABC and EDC such that:
AB ⊥ BD and BD ⊥ DE
C is the midpoint of BD.
The two triangles are drawn below.
Since, AB ⊥ BD and BD ⊥ DE
Therefore, the two triangles are right angled triangle. The triangle ABC is right angled at vertex B. The triangle EDC is right angled at vertex D.
Since, point C is the midpoint of the line segment BD.
Therefore, C divides the line segment BD into two equal parts.
So, segment BC ≅ segment CD (Midpoint theorem)
Now, consider the triangles ABC and EDC.
Statements Reason
1. ∠ABC ≅ ∠CDE Right angles are congruent to each other
2. BC ≅ CD Midpoint theorem. C is midpoint of BD
3. ∠ACB ≅ ∠ECD Vertically opposite angles are congruent
Therefore, the two triangles are congruent by ASA postulate.
So, the second option is correct.
Answer:
arc TSR = 180°
arc US = 110°
arc RU =130°
∠RPQ = 60°
arc QRT = 240°
arc UTQ = 290°
Step-by-step explanation:
arc TSR = 180° because half circle
arc US = 110° because 50° + 60°
arc RU =130° because 180° + 50°
∠RPQ = 60° because vertical to 60°
arc QRT = 240° because 180° + 60°
arc UTQ = 290° because 360° - 70°
To find out if they form a right triangle, find out if two of the sides are perpendicular.
to find out if two sides are perpendicular, find the slopes, if the slopes are negative reciprocals, the two lines are perpendicular.
slope of JK: 2/5
slope of KL: -6/2
slope of JL: -4/7
no negative reciprocal pair, so the triangle is not a right triangle.
Answer:
Option A. is even so both ends of the graph go in the same direction.
Step-by-step explanation:
Graphing the function give we can recognize the factor is even, but at the same time both the ends go in the same direction.