(7,-4);
1 answer:
You might be interested in
Answer: Choice B. k(h(g(f(x))))
For choice B, the functions are k, h, g, f going from left to right.
===========================================================
Explanation:
We have 4x involved, so we'll need f(x)
This 4x term is inside a cubic, so we'll need g(x) as well.
So far we have
g(x) = x^3
g( f(x) ) = ( f(x) )^3
g( f(x) ) = ( 4x )^3
Then note how we are dividing that result by 2. That's the same as applying the h(x) function
And finally, we subtract 1 from this, but that's the same as using k(x)
This leads to the answer choice B.
To be honest, this notation is a mess considering how many function compositions are going on. It's very easy to get lost. I recommend carefully stepping through the problem and building it up in the way I've done above, or in a similar fashion. The idea is to start from the inside and work your way out. Keep in mind that PEMDAS plays a role.
Answer:
89%
Step-by-step explanation:
If he's on time on the previous day, there's a 10% probability he'll be late, which means there's a 90% probability that he'll be on time.
If he's late on the previous day, there's a 20% probability he'll be late, which means there's a 80% probability that he'll be on time.
He's on time on Monday, so there's a 10% probability he'll be late on Tuesday and a 90% probability he'll be on time.
If he's on time on Tuesday, there's a 10% probability he'll be late on Wednesday and a 90% probability he'll be on time.
If he's late on Tuesday, there's a 20% probability he'll be late on Wednesday and a 80% probability he'll be on time.
So the probability he'll be on time on Wednesday is:
0.10 (0.80) + 0.90 (0.90) = 0.89
