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fgiga [73]
3 years ago
7

Help answer pleaseeeeeee

Mathematics
1 answer:
12345 [234]3 years ago
5 0

Answer:

Your answer is C.

Step-by-step explanation:

I answered it on paper. When it comes to explaining I have to be person to person. But I hope this helps. :)

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Put the equation y = x^2 + 26 x + 160 into the form y = ( x − h )^2 + k :
KATRIN_1 [288]

Put the equation y = x^2 + 26 x + 160 into the form y = ( x − h )^2 + k

Given equation is y = x^2 + 26 x + 160

We apply completing the square method

we take coefficient of middle term and then divide by 2  and then square it

coefficient of middle term is 26

Divide by 2, it becomes 13

then we square it (13)^2 = 169

Add and subtract 169

y = x^2 + 26 x +169 - 169 + 160

y = x^2 + 26 x +169 - 9

y = (x + 13)^2 - 9

We got the equation in vertex form

6 0
3 years ago
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No one answering equations with variables on both sides plz help with all
Varvara68 [4.7K]

Answer:

1. x=14

2. x = -2

3.y=3

4.w=2

5.r=5

6. y = 6

7. x = -1

8. y = 1

5 0
3 years ago
How do I determine the range. ​
Nikitich [7]

Answer:

y: (5, -5)

Step-by-step explanation:

5 0
3 years ago
Please help fast please please​
konstantin123 [22]

Answer:

27

12

3

0

3

12

27

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y=3x^2

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8 0
3 years ago
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What is the equation of the quadratic graph with a focus of (1, 1) and a directrix of y = −1?
JulsSmile [24]
Alright,
directix is y=something so it opens down or up

we use
(x-h)²=4p(y-k)
the vertex is (h,k)
and p is distance from focus to vertex
if focus is above directix, p is positive
if focus is below directix, p is negative

so we gts

focus=(1,1)
directix is y=-1
1>-1
focus is above

oh, vertex is in middle of focus and directix
so
beteeen (1,1) and y=-1 is, hmm
that is a distance of 2 vertically
2/2=1
1 down from (1,1) is (1,0)
vertex is (1,0)
p=1

so
(x-1)²=4(1)(y-0)
solving for y to get into f(x)=something form
(x-1)²=4y
y=1/4(x-1)²
f(x)=1/4(x-1)²

4th option
6 0
3 years ago
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