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Rashid [163]
3 years ago
6

How to solve this |9x-12|<-4

Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0
<span> |9x-12|  <  -4

There is no solution for this inequality...

Because an absolute value is NEVER less than an a negative number </span>
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Find f(3) for f(x) = 1/2(4)^x <br> A. 8<br> B. 32<br> C. 6<br> D. 64
Elza [17]
1/2 (4)^3

1/2 x 64

32
7 0
3 years ago
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(PLEASE HELP)
Dovator [93]

Answer:

have a great day

Step-by-step explanation:

7 0
3 years ago
Using the completing-the-square method, rewrite f(x) = x2 + 10x + 7 in vertex form
mr Goodwill [35]

Answer:

f(x) = (x - (-5))^2 + (-18)

Step-by-step explanation:

Given:

f(x) = x^2 + 10x + 7

Rewrite f(x) in vertex form

Solution:

f(x) = ax^2 + bx + c is a quadratic function.

The vertex form of f(x) is a(x - h)^2 + k, where (h, k) is the vertex.

=> f(x) = x^2 + 10x + 7

          = x^2 + 10x + 25 - 18

          = (x + 5)^ - 18

          = (x - (-5))^2 + (-18)

=> f(x) can be rewritten in form of a(x - h)^2 + k, where (h, k) is the vertex, with a = 1, h = -5, k = -18

6 0
3 years ago
A surveyor in a canyon takes measurements and draws the diagram shown.
Fiesta28 [93]

Answer:

\approx 118.4

Step-by-step explanation:

We know two sides and the angle between the sides, so we can use the Law of Cosines. Recall that the Law of Cosines states that:

c^2=a^2+b^2-2abcos(C), where a and b are the sides and C is the angle in between.

Let's substitute 115 for a, 178 for b, and 41 for Angle C.

Thus:

c^2=115^2+178^2-2(115)(178)cos(41)

c^2=44909-40940cos(41)

c=\sqrt{44909-40940cos(41)}

c \approx 118. 4

5 0
3 years ago
Two shapes are shown below, one isosceles triangle and one rectangle. The dimensions can be represented by algebraic expressions
liberstina [14]

Answer:

Perimeter of Isosceles Triangle = 16 units

Step-by-step explanation:

Area of rectangle is given by the formula;

Area = 1/2 × base × height

From the diagram, base = 6x - 6 and height = 6x - 8

Thus,Area = 1/2 × (6x - 6) × (6x - 8)

Area = (3x - 3)(6x - 8) = 18x² - 42x + 24

Secondly, area of rectangle is given by;

Area = length x breadth

So, area of rectangle in question = (6x - 9)(3x - 2) = 18x² - 39x + 18

We are told both the area of the triangle and the rectangle are the same, so let's equate both areas;

18x² - 42x + 24 = 18x² - 39x + 18

18x² will cancel out and rearranging, we have;

24 - 18 = 42x - 39x

6 = 3x

x = 6/3

x = 2

Plugging 2 for x for the height and base of the triangle, we have;

base = 6(2) - 6 and height = 6(2) - 8

Base = 6 and height = 4

So,let's find the slant height of the isosceles triangle.

Dividing the base by 2,we have; 6/2 = 3

So,using Pythagoras theorem, let the slant height be h, so we have;

h² = 3² + 4²

h² = 9 + 16

h² = 25

h = √25

h = 5

2 slant sides of isosceles triangle are the same. So perimeter = 5 + 5 + 6 = 16 units

8 0
3 years ago
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