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3 years ago

Which set of ordered pairs is a function?

Mathematics

1 answer:

melamori03 [73]3 years ago

4 0

Functions can't have multiple y values have the same x value.

[(-5, 1), (-3, 2), (-1, 3) (1, 4), (3, 5)] ** No repeating x-values.

[(-2, 1), (-4, 2), (0,3), (4, 1), (-2,5)]

[(-1, 5), (-1,4), (-1, 3), (-1, 2) (-1, 1)]

[(-6, -4), (-4, -2), (0, 0), (-4, 2) (-6, 4)]

Answer:

[(-5, 1), (-3, 2), (-1, 3) (1, 4), (3, 5)]

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Use the diagram to find the measure of arc. AB and CD and the diameters of the circle F

dybincka [34]

Answer:

11). $m(\widehat{DE})$ = 90°

12). $m(\widehat{AEC})$ = 212°

Step-by-step explanation:

A circle F with AB and CD are the diameters has been given in the figure attached.

11). Since, $m(\widehat{AB})$ = 180°

and $m(\widehat{AB})=m(\widehat{AD})+m(\widehat{DE})+m(\widehat{BE})$

Therefore, $m(\widehat{AD})+m(\widehat{DE})+m(\widehat{BE})$ = 180°

32° + $m(\widehat{DE})$ + 58° = 180°

$m(\widehat{DE})$ = 180° - 90°

= 90°

12. Since, $m(\widehat{AD})=m(\widehat{BC})$ = 32°

$m(\widehat{AEC})$ = $m(\widehat{AB})+m(\widehat{BC})$

= 180° + 32°

= 212°

7 0

3 years ago

Find the reciprocal of 1/5

ivanzaharov [21]

Answer:

Hey! The reciprocal of 1/5 is 5!

Hope this helps :)

~sofia

6 0

4 years ago

6 in<br> 24 in<br><br> I don’t get this at all and I have trouble with math

nekit [7.7K]

What’s the full question?

6 0

2 years ago

Newton’s law of universal gravitation, F=Gm1m2/r²,measures the force of gravity between two masses m1 and m2,where r is the dist

Pavel [41]

Answer:

$G=\frac{Fr^2}{m_1m_2}$

Step-by-step explanation:

Since our equation is $F=\frac{Gm_1m_2}{r^2}$ and we want to solve for G, first we divide both sides by the product $m_1m_2$ , which gives:

$\frac{F}{m_1m_2}=\frac{Gm_1m_2}{m_1m_2r^2}=\frac{G}{r^2}$

So we are left with:

$\frac{F}{m_1m_2}=\frac{G}{r^2}$

Now we multiply both sides by $r^2$ , which gives:

$\frac{Fr^2}{m_1m_2}=\frac{Gr^2}{r^2}=G$

Which gives us our final formula:

$G=\frac{Fr^2}{m_1m_2}$

6 0

3 years ago

1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help

Gnesinka [82]

$\huge \boxed{\mathfrak{Question} \downarrow}$

Simplify :- 1 + - w² + 9w.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\large \sf1 + - w ^ { 2 } + 9 w$

Quadratic polynomial can be factored using the transformation $\sf \: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$ , where $\sf x_{1} and x_{2}$ are the solutions of the quadratic equation $\sf \: ax^{2}+bx+c=0$ .

$\large \sf-w^{2}+9w+1=0$

All equations of the form $\sf\:ax^{2}+bx+c=0$ can be solved using the quadratic formula: $\sf\frac{-b±\sqrt{b^{2}-4ac}}{2a}$ . The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$\large \sf \: w=\frac{-9±\sqrt{9^{2}-4\left(-1\right)}}{2\left(-1\right)} \\$

Square 9.

$\large \sf \: w=\frac{-9±\sqrt{81-4\left(-1\right)}}{2\left(-1\right)} \\$

Multiply -4 times -1.

$\large \sf \: w=\frac{-9±\sqrt{81+4}}{2\left(-1\right)} \\$

Add 81 to 4.

$\large \sf \: w=\frac{-9±\sqrt{85}}{2\left(-1\right)} \\$

Multiply 2 times -1.

$\large \sf \: w=\frac{-9±\sqrt{85}}{-2} \\$

Now solve the equation $\sf\:w=\frac{-9±\sqrt{85}}{-2}$ when ± is plus. Add -9 to $\sf\sqrt{85}$ .

$\large \sf \: w=\frac{\sqrt{85}-9}{-2} \\$

Divide -9+ $\sf\sqrt{85}$ by -2.

$\large \boxed{ \sf \: w=\frac{9-\sqrt{85}}{2}} \\$

Now solve the equation $\sf\:w=\frac{-9±\sqrt{85}}{-2}$ when ± is minus. Subtract $\sf\sqrt{85}$ from -9.

$\large \sf \: w=\frac{-\sqrt{85}-9}{-2} \\$

Divide $\sf-9-\sqrt{85}$ by -2.

$\large \boxed{ \sf \: w=\frac{\sqrt{85}+9}{2}} \\$

Factor the original expression using $\sf\:ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right)$ . Substitute $\sf\frac{9-\sqrt{85}}{2}$ for $\sf\:x_{1}$ and $\sf\frac{9+\sqrt{85}}{2}$ for $\sf\:x_{2}$ .

$\large \boxed{ \boxed {\mathfrak{-w^{2}+9w+1=-\left(w-\frac{9-\sqrt{85}}{2}\right)\left(w-\frac{\sqrt{85}+9}{2}\right) }}}$

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

$\large \sf \: 1 + - w {}^{2} + 9w \\ =\large \boxed{\bf \: 1 - {w}^{2} + 9w}$

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)

4 0

3 years ago