The value 257.3 denotes the range of the middle 50% of all observations in the distribution.
Q1 = 271.8 ; Q2 = 387.9 ; Q3 = 529.1
The Interquartile range is the difference between the the upper quartile and Lower quartile ;
- IQR = 529.1 - 271.8 = 257.3
The value of Q3 depict the 75th percentile of the data
The value of Q1 depicts the 25th percentile of the data
The difference between (Q3 and Q1) ; is the (75th - 25th) = middle 50th percentile of the distribution.
Since the difference between the maximum and minimum value is the range, then 257.3 is the range of the middle 50% of all observations in the distribution.
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Answer: 7
Step-by-step explanation:
Find the prime factors of each term in order to find the greatest common factor (GCF).
Answer:
One standard deviation above the mean means a z-score of 1.0. If we put this into the calculator as normalcdf(1,999) = .159
15.9 percent of the athletes would have a distance greater than 20.56 meters.
Now multiply the number of athletes by the percent.
.159 * 40 = 6.346 = about 6 athletes
c. about 6 athletes
Using the probability and odds concepts, it is found that the odds against it containing a number greater than or equal to 7 is 
.
- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
- An odd is the <u>number of desired outcomes divided by the number of non-desired outcomes</u>.
In the rack, there are 15 balls, numbered from 1 to 15. Of those, <u>6 are less than 7</u>(against it containing a number greater than or equal to 7 is equivalent to it containing a number less than 7), thus:
- There are 6 desired outcomes.
- There are 9 non-desired outcomes.
The odd is:
The odds against it containing a number greater than or equal to 7 is .
A similar problem is given at brainly.com/question/21094006
