Answer:
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Step-by-step explanation:
haha thanks for the points!
The answer is: " 12 " .
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→ " x = 12 " .
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To solve:
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3x - 1 = x + 23 ; Solve for "x" ;
Subtract "x" from each side of the equation; & add "1" to each side of the equation;
3x - 1 - x + 1 = x + 23 - x + 1 ;
to get:
2x = 24 ;
Divide each side of the equation by "2" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
2x/2 = 24/2 ;
to get:
x = 12 .
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Let us check our answer, by plugging in "12" for "x" ; on EACH side of the original equation; to see if the equation holds true; {that is, to see if each side of the original equation is equal, when "x = 12" } ; as follows:
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3x - 1 = x + 23 ;
Substitute "12" for "x" on each side ;
3(12) - 1 =? (12) + 23 ??
36 - 1 =? 35 ??
35 =? 35?? Yes!
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Answer:
Step-by-step explanation:
Given that X is uniform in the interval (0,A)
X is continuous since it represents the distance
A fire station is to be located along a road of length A, A < q. If fires occur at points uniformly chosen on (0, A), we should find where the station be located so as to minimize the expected distance from the fire
Distance can be taken as absolute values here as either side is the same.
E(|x-a|] is to be minimum
E(|x-a|)=E(x-a) for 0<x<a
=E(a-x), for a<x<A
Using integral we find this value
Using calculus we find that f" is positive so when f' =0 we get solution
f'(a) =0 gives
Hence fire station to be located at the mid point of 0 and A
