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3 years ago

How do you factor 8x^2+18x+9=0

1 answer:

8 0

First off, do a prime factoring of the constant and leading coefficient, namely 9 and 8 respectively.

so a prime factoring of 8 is 2*2*2, and a prime factoring of 9 is 3*3.

so, those are the factors... now, how do we produce products that gives us the middle coefficient +18?

well, let's see hmmmm 2 * 3 * 3 and 2 * 3....so that's 18 + 6, that's 24.. .so... no good is not 18, let's try again.

2*2*3 and 2 * 3, so that's 12 + 6, now, that's +18

so we'll use those, 2*2*3 and 2*3, or 4 * 3 an 2 * 3, (4x + 3)(2x + 3) = 0.

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Advocard [28]

Answer:

y - 7 = 4(x - 6)

y - 7 = 4x - 24

y = 4x - 24 + 7

y = 4x - 17

8 0

3 years ago

Read 2 more answers

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Yuliya22 [10]

For every one stamp James has Roy has twice as much. So the ratio would be 1/2. Hope this helped!

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3 years ago

Two solid spheres have surface areas of 1441 cm? and 2567 cm² respectively. They are melted and recast to form a larger sphere.

Tju [1.3M]

Surface area of small sphere = 1441cm^2

Surface area of bigger sphere = 2567cm^2

Surface area of largest sphere = 1441 + 2567

= 4008cm²

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7 0

2 years ago

The fish tank has side lengths 20in, 10in and height 15in. The water level is two inches below the top of the tank. A glass sphe

Kitty [74]

Answer:

Part 1) The new distance from the water to the top of the tank is $1.979\ in$

Part 2) The maximum number of balls that can be put into the tank with the tank not overflowing is 95

Step-by-step explanation:

step 1

Find the total volume of the tank

$V=20*10*15=3,000\ in^{3}$

step 2

Find the volume of the tank if the water level is two inches below the top of the tank

$V=20*10*(15-2)=2,600\ in^{3}$

step 3

Find the volume of the glass sphere

The volume of the glass sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$r=1\ in$

assume

$\pi=3.14$

substitute

$V=\frac{4}{3}(3.14)(1)^{3}$

$V=4.2\ in^{3}$

step 4

What is the new distance from the water to the top of the tank?

we know that

$2 in -----> represent (3,000-2,600)=400\ in^{3}$

using proportion

Find how many inches correspond a volume of $4.2\ in^{3}$

$\frac{2}{400}\frac{in}{in^{3}}=\frac{x}{4.2}\frac{in}{in^{3}}\\ \\x=4.2*2/400\\ \\x=0.021\ in$

The new distance from the water to the top of the tank is

$2-0.021=1.979\ in$

step 5

Find how many of these balls can be put into the tank with the tank not overflowing

we know that

The volume of one ball is equal to $4.2\ in^{3}$

using proportion

$\frac{1}{4.2}=\frac{x}{400}\\ \\x=400/4.2\\ \\x=95.23\ balls$

therefore

The maximum number of balls that can be put into the tank with the tank not overflowing is 95

4 0

3 years ago

Find the volume of the sphere with a diameter of 22 and round to the nearest 10

maksim [4K]

Answer:

$\huge\boxed{\sf Volume = 16728.8 \ units^3}$

Step-by-step explanation:

Diameter = 22 units

Radius = 11 units

$\rule[225]{225}{2}$

$\sf Volume = \frac{4}{3} \pi r^3\\\\Volume = \frac{4}{3} (3.14)(11)^3\\\\Volume = \frac{4}{3} (3.14)(1331)\\\\Volume = \frac{4}{3} (4184.5)\\\\\bold{Volume = 16728.8 \ units^3}$

$\rule[225]{225}{2}$

Hope this helped!

<h2>~AnonymousHelper1807</h2>

7 0

3 years ago