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Yanka [14]
3 years ago
14

Right Triangles and Trigonometry Homework 5

Mathematics
1 answer:
gavmur [86]3 years ago
4 0

this picture has bad quality, please resend with better picture so i can answer all of them

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What is the angle of rotation of the image?<br>A. 60°<br>B. 90°<br>C.120°<br>D. 180°<br>​
lisov135 [29]

Answer:

It would be great if you would provide the image itself. I will totally answer your question.

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3 years ago
For 25 points:<br> x + 5 = 10<br> 2x + ? = 20<br> Answer for "?"
Phoenix [80]

Answer:

x= 5

?=10

Step-by-step explanation:

Mark me Brainliest Pls

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2 years ago
What is the greatest common factor of 54,30,78?  pleaseeeeee help lol 
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Greatest\ common\ factor\ is\ the\ highest\ number\ by\ witch\ 54\ and\ 30\\and\ 78\ can\ be\ divided\\\\&#10;54:2\\&#10;27:3\\9:3\\3:3\\\\&#10;30:2\\&#10;15:3\\&#10;5:5\\\\78:2\\39:3\\13:13&#10;\\\\GCF=2*3=6\\\\Greatest\ common\ factor\ of\ 54\ and\ 30\ and\ 78\ is\ equal\ to\ 6.&#10;
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3 years ago
Can somebody please walked through this, I'm so confused and I have a test in 6 hours...
erastova [34]

Answer:

Q3: x = 4, y = 4, z = 4

Q4: x = 6, y = 0, z = -4

Step-by-step explanation:

Question 3: Simultaneous equations requires us to solve for x, y and z.

Since all three equations have a z in them, I will first solve for z.

Substitute in the first and third equation into the second equation.

First equation: x = 5z - 16

Second Equation: -4x + 4y - 5z = -20

Third equation: y = -z + 8

Substituting in x = 5z - 16 and y = -z + 8 for the x and y in the second equation.

-4(5z - 16) + 4(-z + 8) - 5z = -20

Expand

-20z + 64   - 4z + 32   - 5z = -20

Simplify and solve for z by putting all the numbers on one side and all the z's on the other side of the equals

-20z - 4z - 5z = -20 - 32 - 64

-29z = -116

z = -116/-29

z = 4

Substitute in this z value into the first and last equation and then solve for x and y

x = 5z - 16

x = 5(4) - 16

x = 20 - 16

x = 4

And

y = -z + 8

y = -(4) + 8

y = 4 (Its just a coincidence that they all equal to 4, I promise)

Question 5: A little bit harder of a question. Since the first and second equation both only have y and z, we can solve it using the elimination method.

Rearrange them so that the letters are on one side and numbers on the other side.

First equation: y + 6z = -24

Second equation: z + 2y = -4

I will choose to eliminate the y (You can choose either or)

Multiply the first equation by 2

2(y + 6z = -24)

2y + 12z = -48

Now that 2y is in both equations, we can minus one equation from the other to eliminate the y (I will minus the second from the first)

First Eq: 2y + 12z = -48

Second Eq: z + 2y = -4

2y - 2y = 0y

12z - z = 11z

-48 - (-4) = -44

Type these answers into a new equation

0y + 11z = - 44

Since y is 0, ignore it. Solve for z

11z = -44

z = -44/11

z = - 4

Substitute our z into either the first or second equation and solve for y (It doesnt matter which one you choose, I just did the second equation)

z + 2y = -4

(-4) + 2y = -4

2y = -4 + 4

2y = 0

y = 0

Substitute in our y and z values into the third equation and solve for x

-6x - 6y - 6z = -12

-6x - 6(0) - 6(-4) = -12

-6x - 0 + 24 = -12

-6x = -12 - 24

-6x = -36

x = -36/-6

x = 6

6 0
3 years ago
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Which statement is true?
LuckyWell [14K]

Answer:I think it is C

Step-by-step explanation:I think it i C

5 0
3 years ago
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