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katrin [286]
4 years ago
6

Complete each statement in the steps to solve x2 – 6x – 7 = 0 using the process of completing the square. Isolate the constant b

y both sides of the equation. Add to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced. Write the trinomial x2 – 6x + 9 as squared. Use the square root property of equality to get x – 3 = ± . Isolate the variable to get solutions of –1 and 7.
ANSWERS:
Adding 7 to
9
x-3
4
Mathematics
2 answers:
Oksi-84 [34.3K]4 years ago
8 0

Answer:

1 adding 7 to

2 9

3 x-3

4 4

Step-by-step explanation:

Vera_Pavlovna [14]4 years ago
4 0

Answers: Using the process of completing the square:

1. Isolate the constant by <u>adding 7 to</u> both sides of the equation:

x^2-6x-7+7=0+7

x^2-6x=7

2. Add <u>9</u> to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced:

x^2-6x+9=7+9

x^2-6x+9=16

3. Write the trinomial x2 – 6x + 9 as squared:

<u>(x-3)^2</u> = 16

4. Use the square root property of equality to get x – 3 = ±<u>4</u> .

sqrt[ (x-3)^2 ] = ± sqrt(16)

x-3 = ±4

5. Isolate the variable to get solutions of –1 and 7.

x-3 = ±4

x-3+3 = ±4+3

x = ±4+3

x1=-4+3→x1=-1

x2=+4+3→x2=7

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