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3 years ago

What is the area of the polygon

Mathematics

2 answers:

Paul [167]3 years ago

8 0

Split this figure into 3 shapes: 2 triangles and 1 trapezoid

Area of top triangle = 1/2(7)(2) = 7 square units
Area of bottom triangle = 1/2(3)(7) = 10.5 square units
Area of trapezoid = 1/2(3 + 6)(4) = 18 square units

Area of the polygon = 7 + 10.5 + 18 = 35.5 square units

vlada-n [284]3 years ago

6 0

Look at the picture.
$A_I=\dfrac{7\cdot2}{2}=7\\\\A_{II}=\dfrac{4\cdot3}{2}=6\\\\A_{III}=\dfrac{7\cdot3}{2}=10.5\\\\A_{IV}=3\cdot4=12\\\\The\ area\ of\ the\ polygon\\\\A=A_I+A_{II}+A_{III}+A_{IV}\\\\A=7+6+10.5+12=35.5\ un^2$

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Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

What angle does the piece of pie form? picture is added

Gwar [14]

Answer:

It forms a 90 degree angle

Step-by-step explanation:

Since a circle is 360 degrees, 1/4 of that would be 90.

8 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP! 20 POINTS AND ILL GIVE YOU A BRAINLIEST!!

nikitadnepr [17]

It is A because you are adding 3 to in if you were to subtract then it will go down not up.

7 0

3 years ago

Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!

forsale [732]

$1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}$

Step-by-step explanation:

The given equation is $4x^{2}-8x-1$

Let $a$ be the coefficient of $x^{2}$

Let $b$ be the coefficient of $x$

Let $c$ be the constant.

Then the roots α,β for the equation $ax^{2}+bx+c$ are $\dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}$

So,α= $\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}$

β= $\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}$ .

So the roots are $1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}$

5 0

3 years ago

What was the depth of the submarine after 6 minutes

pishuonlain [190]

-120 + 13m, at time m = 6, would be -120 + 78, or -42 feet.

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3 years ago