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3 years ago

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Two requirements to be employed within a certain company are that you must be at least 18 years of age and have had more than on

e job-related work experience. Write and graph two inequalities that represent the requirements.

1 answer:

sergiy2304 [10]3 years ago

4 0

Answer:

Step-by-step explanation:

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Please answer and explain. 25pts

AVprozaik [17]

C) x<8 and x>10
c) all real Numbers (multiply the -2 to the parenthesis and you get the same equation on both sides which means all real numbers)
C) x is greater than or equal to -3 (solid circle with the line towards positive.)
A) 24 ( distribute then subtract p from both sides)
B) d-12 $\geq$ 51; d $\geq$ 63

7 0

2 years ago

Read 2 more answers

F(x) = -2x + 5<br> f ( ) = 13

scZoUnD [109]

Answer:

Okay, I haven't done this a long time however I believe with this you have to solve the equation by doing substitution.

Step-by-step explanation:

so, if f (x) equals 13, you replace the x in the equation to 13.

f(x)=-2x+5

f(x)=-2(13)+5

f(x)=26+5

f(x)=31

I believe 41 would be your answer. Hope this is right and it helped!

4 0

3 years ago

Someone just answer this math question thingie lol. you’ll get 33 points G

Stels [109]

1) $(-2x+4)+(x-6)$ is simplified into $=-x-2$

2) $(uv-3)+(4uv+1)$ is simplified into $5uv-2\\$

3) $(11x-8)-(2x+3)$ is simplified into $-9x-11$

4) $(x^2-4)-(x-2)$ is simplified into $x^2-x-2$

5) $(12-3t-7t^2)+(1+3t-t^2)$ is simplified into $-8t^2+13$

Step-by-step explanation:

We need to solve the polynomials.

1) $(-2x+4)+(x-6)$

Solving:

$(-2x+4)+(x-6)\\=-2x+4+x-6\\Combining\,\,like\,\,terms:\\=-2x+x+4-6\\=-x-2$

So, $(-2x+4)+(x-6)$ is simplified into $=-x-2$

2) $(uv-3)+(4uv+1)$

Solving:

$(uv-3)+(4uv+1)$

Expanding:

$=uv-3+4uv+1\\Combining\,\,like\,\,terms:\\=uv+4uv-3+1\\=5uv-2\\$

So, $(uv-3)+(4uv+1)$ is simplified into $5uv-2\\$

3) $(11x-8)-(2x+3)$

Solving:

$(11x-8)-(2x+3)$

Expanding:

$=11x-8-2x-3\\Combining\,\,like\,\,terms:\,\,\\=11x-2x-8-3\\=-9x-11$

So, $(11x-8)-(2x+3)$ is simplified into $-9x-11$

4) $(x^2-4)-(x-2)$

Solving:

$(x^2-4)-(x-2)$

Expanding:

$=x^2-4-x+2\\Combining\,\,like\,\,terms:\\=x^2-x-4+2\\=x^2-x-2$

SO, $(x^2-4)-(x-2)$ is simplified into $x^2-x-2$

5) $(12-3t-7t^2)+(1+3t-t^2)$

Solving:

$(12-3t-7t^2)+(1+3t-t^2)$

Expanding:

$=12-3t-7t^2+1+3t-t^2\\Combining\,\,like\,\,terms:\\=12+1-3t+3t-7t^2-t^2\\=13+0t-8t^2\\=-8t^2+13$

So, $(12-3t-7t^2)+(1+3t-t^2)$ is simplified into $-8t^2+13$

Keywords: Solving Polynomials

Learn more about solving Polynomials at:

#learnwithBrainly

5 0

2 years ago

Read 2 more answers

Will I ever get an answer?

JulsSmile [24]

(5/8) / (3/8) =
5/8 * 8/3 =
5/3 =
1 2/3....a = 1, b = 2, c = 3

5 0

2 years ago

Multiple please help me out. (picture is for question 4)

Cloud [144]

Answer:

1. 9/10

2. 1/5

3. 4/9

4. 1

Step-by-step explanation:

The general equation of the line is:

(y - y0) = m ( x - x0), where "m" represents the slope is: (y1 - y0) / (x1 - x0).

1. From the statement we know that (x1, y1) = (18, 17) and (x0, y0) = (8,8)

Then the slope is:

m= (y1 - y0) / (x1 - x0) = (17 - 8)/(18 - 8) = 9/10.

The slope is 9/10.

2. From the statement we know that (x1, y1) = (8, 9) and (x0, y0) = (3,8)

Then the slope is:

m= (y1 - y0) / (x1 - x0) = (9 - 8)/(8 - 3) = 1/5.

The slope is 1/5.

3. From the statement we know that (x1, y1) = (15, 15) and (x0, y0) = (6,11)

Then the slope is:

m= (y1 - y0) / (x1 - x0) = (15 - 11)/(15 - 6) = 4/9.

The slope is 4/9.

4. From the graph, we know that the line passes through the points (-5, -4) and (-7, -6). So we know that (x1, y1) = (-5, -4) and (x0, y0) = (-7,-6).

Then the slope is:

m= (y1 - y0) / (x1 - x0) = (-4 - (-6))/(-5 - (-7)) = 2/2 = 1.

The slope is 1.

4 0

3 years ago