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hammer [34]
2 years ago
5

If CP of an item is Rs 7000, If SP of item is Rs 9100 Find the profit percentage.​

Mathematics
1 answer:
Mama L [17]2 years ago
5 0

Step-by-step explanation:

please mark me as brainlest

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Clear parentheses and combine like terms:​
mihalych1998 [28]

Answer:

-3p - p²

Last option

Step-by-step explanation:

Step 1: Write out expression

2p - 7p² - 5p + 6p²

Step 2: Combine like terms (p²)

-p² + 2p - 5p

Step 3: Combine like terms (p)

-p² - 3p

Step 4: Rewrite

-3p - p²

7 0
3 years ago
What is the prime factorization of 210
SashulF [63]

Answer: 2*3*5*7


Step-by-step explanation:


6 0
2 years ago
Read 2 more answers
Find the volume of the cylinder. Round your answer to the nearest tenth
valentinak56 [21]
I think it's 85 but Is this like a multiple choice question?
8 0
2 years ago
Read 2 more answers
Finf the diffrence write your answer in simplest form 2/7+2/5
Fed [463]
The difference (the answer of a subtraction problem) is:
2/7 - 2/5  -->  10/35 - 14/35 = -4/35

The answer sum (the answer of an addition problem) is:
2/7 + 2/5  -->  10/35 + 14/35 = 24/35

Hope this helps.
4 0
3 years ago
Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits
scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

x^{2} + 3x - 8^{- 14} = 0

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

The above solution is for the quadratic equation of the form:

ax^{2} + bx + c = 0  

x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}

From the given eqn

a = 1

b = 3

c = - 8^{- 14}

Now, using the above values in the formula mentioned above:

x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)

Now, Rationalizing the above eqn:

x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}

x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}

Solving the above eqn:

x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}

Solving with the help of caculator:

x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}

The precise value upto three decimal places comes out to be:

x_{1, 1'} = 0.758\times 10^{- 14}

5 0
3 years ago
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