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zepelin [54]
3 years ago
5

Calculate the slope: rise: 37 run: 63

Mathematics
1 answer:
valentinak56 [21]3 years ago
6 0

calculate rise over run = 37 ÷ 63

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Given: ∆ABC, m∠C = 90°
cluponka [151]

Answer:

LB = 12ft

Step-by-step explanation:

m< CAB = 60 because of the triangle sum theorem

We can use triangle sum theorem to find the measure of all the angles in triangle CLA.

m< CAL = 60/2 = 30, because AL is a angle bisector

The m<CLA = 60 because of the triangle sun theorem

Then we can use properties of a 30 - 60 - 90 triangle.

LA = 12

Then, we also know that m< ALC = 30 because that is what is reamining of that angle.

So, we can see that triangle ALB is a isosceles triangle.

Then LA would equal LB by the definition of a Isosceles triangle, so LB would be 12 as well.

5 0
3 years ago
Y is directly proportional to the positive square root of x.
maxonik [38]

Answer:

y = 2

Step-by-step explanation:

from the question which says that y is directly proportional to the positive square root of x can be expressed mathematically by saying

y ∝ √x

y = k√x..................................................... where k is the constant of proportionality.

y = 12, x = 9 , k = ?

from

y = k√x

12 = k√9

12 =3k

divide both sides by the coefficient of k which is 3

12/3 = 3k/3

4 = k

therefore K = 3

now, to find the value of y when x = 1/4

from y = k√x

y = 4√1/4

y = 4 × 1/2

y = 2

therefore the value of y when x = 1/4  in this expression y = k√x  is 2

6 0
3 years ago
Write the equation of the parabola with a vertex (3,5) and a focus of (3,9)
Kay [80]

<u>Answer-</u>

\boxed{\boxed{(x-3)^2=16(y-5)}}

<u>Solution-</u>

Given,

the parabola has vertex at (3,5) and focus at (3,9)

It can be easily noticed that focus and vertex lie on the same vertical line,x=3

Hence, the axis of symmetry is a vertical line ( a line perpendicular to x-axis). Also, the focus lies to the top of the vertex so the parabola will open up upwards.

General form of parabola vertex at (h, k)and vertical line of symmetry is,

(x-h)^2=4a(y-k)

Putting the values,

(x-3)^2=4a(y-5)

We can find the value of 'a' which is distance between vertex and focus by using distance formula,

=\sqrt{(3-3)^2-(9-5)^2}\\\\=\sqrt{4^2}\\\\=4

Taking only +ve value, as the parabola opens upwards.

then the equation becomes,

(x-3)^2=4\times 4(y-5)\\\\(x-3)^2=16(y-5)

8 0
3 years ago
Read 2 more answers
Compatible numbers are numbers in a problem that are easy to compute blank
matrenka [14]
Compatible numbers are numbers in a problem that are easy to conpute mentally
4 0
3 years ago
On a coordinate plane, a line goes through (negative 3, 2) and (2, negative 1). A point is at (3, 0). What is the equation of th
stepladder [879]

Answer:

5x -3y = 15

Step-by-step explanation:

First find the slope of the line through ( -3,2) and (2,-1)

m = (y2-y1)/(x2-x1)

   =( -1-2)/(2--3)

   = -3/(2+3)

    = -3/5

We want a line that is perpendicular so the slopes will multiply to -1

m * -3/5 = -1

Multiply each side by -5/3

m * -3/5 * -5/3 = -1 *-5/3

m = 5/3

The slope of the perpendicular line is 5/3

We have a slope and a point

Using point slope form

y-y1 = m(x-x1)

y-0 = 5/3( x-3)

y = 5/3( x-3)

Distribute

y = 5/3x -5

Multiply each side by 3

3*y = 3(5/3x -5)

3y = 5x - 15

Subtract 5x from each side

-5x+3y = -15

Multiply each side by -1

5x -3y = 15

7 0
3 years ago
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