5x + 3y = - 53
the equation of a line in ' slope- intercept form ' is y = mx + c
where m is the slope and c the y-intercept
rearrange 3x - 5y = - 15 into this form to obtain m → (subtract 3x from both sides)
- 5y = - 3x - 15 → divide all terms by - 5 )
y = x + 3 → in slope-intercept form with m =
given a line with slope m then the slope m₁ of a line perpendicular to it is
m₁ = - = - 1 ÷ = -
partial equation is y = - x + c
to find c substitute ( - 7, - 6) into the partial equation
- 6 = + c ⇒ c = - 6 - = -
y = - x - → in slope intercept form
multiply all terms by 3
3y = - 5x - 53 → ( add 5x to both sides )
5x + 3y = - 53 → in standard form
Answer is c
something that helps me is
soh- opposite hypotenuse cah - adjacent and hypotenuse toa- opposite and adjacent
soh cah toa
Answer:
wer here. Link below!
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bit.
Step-by-step explanation:
It is already in identity.
cos (x - y) - cos (x + y) = 2 sin(x) sin (y)
Answer:
there is not table
Step-by-step explanation: