All categories

3 years ago

Write ways to represent the fraction 10/9.

Mathematics

2 answers:

kicyunya [14]3 years ago

8 0

Answer:

mixed number form 1 1/9

decimal form 1.11111111111111 it goes on forever

percent form 111.111111111111% it goes on forever (again)

Step-by-step explanation:

i hope that helps!

dusya [7]3 years ago

6 0

Answer:

1 1/9

Step-by-step explanation:

10/9, you get 1 as the whole number.

You have a 1 left over when dividing 10 and 9. the 1 will be over 9.

Giving you 1 as the whole number and 1/9 next to it.

You might be interested in

Find the inverse of f(x)=7.50x

m_a_m_a [10]

there is no inverse though

8 0

2 years ago

A square and a rectangle have equal area.The rectangle is 64 cm by 81 cm. What is the perimeter of the square?

Fittoniya [83]

Answer:

2592 cm

Step-by-step explanation:

square area = x²

rectangle area = bh

x² = bh

since the areas are equal

b and h are in the problem as 64 and 81

x² = 64x81

x² = 5184

divide by 2

x = 2592 cm

6 0

3 years ago

The area of a rectangle with base b and height h is bh. A rectangular sports goal is 10ft wide and 8 ft high. Find the area of t

bogdanovich [222]

A = bh

A = 10(5)

A = 50 ft2

8 0

3 years ago

Read 2 more answers

find the coordinates of the vertices of the triangle after a reflection across the parallel lines; first across the line x= -2 a

Kamila [148]

Answer:

Step-by-step explanation:

that the coordinates of the vertices of the triangle after a reflection across the parallel lines .

8 0

3 years ago

Verify by substitution whetherthe given functions are solutions of the given DE. Primes denote derivatives with respect to x.y!!

julia-pushkina [17]

Complete Question

The complete question is shown on the first uploaded

Answer:

$y_1$ is not a solution of the differential equation

$y_2$ is not a solution of the differential equation

$y_3$ is not a solution of the differential equation

Step-by-step explanation:

The differential equation given is $y'' + y' = cos2x$

Let consider the first equation to substitute

$y_1 = cosx +sinx$

$y_1' = -sinx +cosx$

$y_1'' = -cosx -sinx$

$y_1'' - y_1' = -cosx -sinx -sinx +cosx$

$y_1'' + y_1' = -2sinx$

$-2sinx \ne cos2x$

This means that $y_1$ is not a solution of the differential equation

Let consider the second equation to substitute

$y_2 = cos2x$

$y_2' = -2sin2x$

$y_2'' = -4cos2x$

$y_2'' + y_2' = -4cos2x-2sin2x$

$-4cos2x-2sin2x \ne cos2x$

This means that $y_2$ is not a solution of the differential equation

Let consider the third equation to substitute

$y_3 = sin 2x$

$y_3' = 2cos 2x$

$y_3'' = -4sin2x$

$y_3'' + y_3' = -4sin2x - 2cos2x$

$-4sin2x - 2cos2x \ne cos2x$

This means that $y_3$ is not a solution of the differential equation

6 0

3 years ago