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masha68 [24]
3 years ago
12

What is 645 divided by 5

Mathematics
3 answers:
PilotLPTM [1.2K]3 years ago
6 0
You could do this on your hands but it would take forever and I don't think you have enough fingers. 50 / 5=10 so do that 12 more times.

600 / 5=120

45 / 5= 9

so it should be 129.


dusya [7]3 years ago
4 0
645/5 = 129 
thats the answer
MicahUwU2 years ago
0 0

129 no remainders

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Solve the equation 3 - 2x = 9<br><br> a) x = 3<br> b)x = -3<br> c) x = 6<br> d) x = -6
Elza [17]

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<h2><em>X=</em><em>-</em><em>3</em></h2>

<em>Option </em><em>B </em><em>is </em><em>correct </em><em>.</em><em>.</em><em>.</em>

<em>solution \\ 3 - 2x = 9 \\ or \:  - 2x = 9 - 3 \\ or \:  - 2x = 6 \\ or \: x =  \frac{6}{ - 2}  \\ x =  - 3</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em>

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3 0
3 years ago
Read 2 more answers
The following probability distributions of job satisfaction scores for a sample of information systems (IS) senior executives an
Mashcka [7]

Answer:

Step-by-step explanation:

To calculate ;

1) the expected value of the job satisfaction score for senior executives ;

expected value = Summation (Px)

= 1 x 0.05 + 2 x 0.09 + 3 x 0.03 + 4 x 0.42 + 5 x 0.41

= 4.05

2) the expected value of the job satisfaction score for middle managers;

= 1 x 0.04 + 2 x 0.10 + 3 x 0.12 + 4 x 0.46 + 5 x 0.28

= 3.84

c) the variance of job satisfaction scores for executives and middle managers (to 2 decimals).

Executives ; Variance = Summation(PX^2 - Summation(PX)^2

i) For Executive Managers = 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2 = 1.246 = 1.25

ii) for middle managers ; 1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 = 1.134 = 1.13

d) the standard deviation of job satisfaction scores for both probability distributions (to 2 decimals). Executives, Middle managers;

For Executives = square root [ 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2] = 1.12

For Middle Managers ; Square root [1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 ] = 1.06

e) from the values gotten for the variance of both executive and middle managers, the variance of the former is more than that of the latter as such higher satisfaction with the executive managers.

5 0
3 years ago
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