3.22$ because your originally spending 35$ so the added 3.22$ makes up 38.22$
5 would be the answer to it
R = 25 cm = 0.25 m
α = 2.00 rad /s²
T(heta) = 4 π
ω = T(heta)/ t
ω = α t
α t = 4 π / t
t ² = 2 π
t = √ ( 2π ) = 2.5 s
ω = α t = 2 · 2.5 = 5 rad/s
v = ω r = 5 · 0.25 = 1.25 m/s
(1) a (rad) = ω² r = 25 · 0.25 = 6.25 m/s²
(2) a (rad) = v² / r = ( 1.25 )² / 0.25 = 0.15625 / 0.25 = 6.25 m/s²
Answer:
The correct option is (B) Fail to reject the null hypothesis with either α = .05 or α = .01
Step-by-step explanation:
Consider the provided information.
The size of sample 1 = n1 = 10
The size of sample 2 = n2 = 10
It is given that the test statistic is: t = 2.095
For α = 0.05
ndf = n1 + n2 - 2
Substitute the respective values in the above formula.
ndf = 10 + 10 - 2 = 18
Two Tailed Test:
From the table, critical value of t = 2.1009
But the calculated value of t = 2.095 which is less than critical value of t = 2.1009, Fail to reject
.
For α = 0.01
From the table, critical value of t = 2.8784
But the calculated value of t = 2.095 which is less than critical value of t = 2.8784, Fail to reject
.
Hence, the correct option is (B) Fail to reject the null hypothesis with either α = .05 or α = .01