R = 25 cm = 0.25 m
α = 2.00 rad /s²
T(heta) = 4 π
ω = T(heta)/ t
ω = α t
α t = 4 π / t
t ² = 2 π
t = √ ( 2π ) = 2.5 s
ω = α t = 2 · 2.5 = 5 rad/s
v = ω r = 5 · 0.25 = 1.25 m/s
(1) a (rad) = ω² r = 25 · 0.25 = 6.25 m/s²
(2) a (rad) = v² / r = ( 1.25 )² / 0.25 = 0.15625 / 0.25 = 6.25 m/s²

8 0

3 years ago

You purchased 150 feet of chain that normally sells for $0.15 per inch. You were charged $22.50 for the sale. Was the price corr

Tema [17]

The correct answer is 270, I believe.

6 0

2 years ago

An independent-measures research study uses two samples, each with n= 10 participants. If the data produce a t statistic of t =

solong [7]

Answer:

The correct option is (B) Fail to reject the null hypothesis with either α = .05 or α = .01

Step-by-step explanation:

Consider the provided information.

The size of sample 1 = n1 = 10

The size of sample 2 = n2 = 10

It is given that the test statistic is: t = 2.095

For α = 0.05

ndf = n1 + n2 - 2

Substitute the respective values in the above formula.

ndf = 10 + 10 - 2 = 18

Two Tailed Test:

From the table, critical value of t = 2.1009

But the calculated value of t = 2.095 which is less than critical value of t = 2.1009, Fail to reject $H_0$ .

For α = 0.01

From the table, critical value of t = 2.8784

But the calculated value of t = 2.095 which is less than critical value of t = 2.8784, Fail to reject $H_0$ .

Hence, the correct option is (B) Fail to reject the null hypothesis with either α = .05 or α = .01

4 0

3 years ago