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xxMikexx [17]
3 years ago
13

O you consider yourself to be good or bad at taking tests? Why? Do you listen more to your Explorer or Judge voice? Why? How do

you study for your tests?
SAT
1 answer:
kolbaska11 [484]3 years ago
6 0
I’d say I’m alright at taking tests, the trick is to write down the information you think you’ll forget at the beginning of the test as well as budget your time. Let’s say you have a 20 question test with 35 minutes to complete it, answer the ones you know first, then go back and use process of elimination to complete the rest. Another thing you can do if you’re having trouble concentrating is after every 4 question you complete, give yourself roughly 3 minutes to doodle something quickly. This can help relive your frustration as well as increasing your creativity to help you on the test. I hope that helps!
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Which details in the passage describe an atmosphere of desolation? select two options. "how shall i tell what i saw?" "but the t
djyliett [7]

The details in the passage that depicts an atmosphere of desolation are:

  • <em>"but the towers themselves look blind"</em>
  • <em>"shattered image of a man or a god"</em>

<h3>What is Desolation?</h3>

The word desolation refers to a state of ruin or being deserted. It also implies sadness as a result of loneliness or grief.

The statement,<em> "but the towers themselves look blind"</em>, shows a state of ruin or being deserted.

Also, <em>"shattered image of a man or a god"</em><em> </em>depicts same state of desolation.

Therefore, the details in the passage that depicts an atmosphere of desolation are:

  • <em>"but the towers themselves look blind"</em>
  • <em>"shattered image of a man or a god"</em>

<em />

Learn more about desolation on:

brainly.com/question/9778563

7 0
2 years ago
At papa john's you are deciding on what you want for dinner.
kondaur [170]
Give brainliest pls: a cheese pizza
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2 years ago
Use series to approximate the definite integral i to within the indicated accuracy. i = 1/2 x3 arctan(x) dx 0 (four decimal plac
Valentin [98]

The expression \int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx  is an illustration of definite integrals

The approximated value of the definite integral is 0.0059

<h3>How to evaluate the definite integral?</h3>

The definite integral is given as:

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx

For arctan(x), we have the following series equation:

\arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1}}{2n + 1}}

Multiply both sides of the equation by x^3.

So, we have:

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1}}{2n + 1}}  * x^3

Apply the law of indices

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1 + 3}}{2n + 1}}

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Evaluate the product

x^3 \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Introduce the integral sign to the equation

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =\int\limits^{1/2}_{0} \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Integrate the right hand side

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}} ]\limits^{1/2}_{0}

Expand the equation by substituting 1/2 and 0 for x

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}} ] - [ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{0^{2n + 4}}{2n + 1}} ]

Evaluate the power

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}} ] - 0

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}}

The nth term of the series is then represented as:

T_n = \frac{(-1)^n}{2^{2n + 5} * (2n + 4)(2n + 1)}

Solve the series by setting n = 0, 1, 2, 3 ..........

T_0 = \frac{(-1)^0}{2^{2(0) + 5} * (2(0) + 4)(2(0) + 1)} = \frac{1}{2^5 * 4 * 1} = 0.00625

T_1 = \frac{(-1)^1}{2^{2(1) + 5} * (2(1) + 4)(2(1) + 1)} = \frac{-1}{2^7 * 6 * 3} = -0.0003720238

T_2 = \frac{(-1)^2}{2^{2(2) + 5} * (2(2) + 4)(2(2) + 1)} = \frac{1}{2^9 * 8 * 5} = 0.00004340277

T_3 = \frac{(-1)^3}{2^{2(3) + 5} * (2(3) + 4)(2(3) + 1)} = \frac{-1}{2^{11} * 10 * 7} = -0.00000634131

..............

At n = 2, we can see that the value of the series has 4 zeros before the first non-zero digit

This means that we add the terms before n = 2

This means that the value of \int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx to 4 decimal points is

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.00625 - 0.0003720238

Evaluate the difference

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.0058779762

Approximate to four decimal places

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.0059

Hence, the approximated value of the definite integral is 0.0059

Read more about definite integrals at:

brainly.com/question/15127807

5 0
2 years ago
What is a pilgrimage church? a. A church frequently visited because of the relics of saints. b. A church where pilgrims would wo
Oksi-84 [34.3K]

A) A church frequently visited because of the relics of saints.

7 0
2 years ago
How many moles of rbi are required to make 350 ml of a 3. 00m solution?
Nimfa-mama [501]
Molarity = number of moles of solvent / volume of solution (in liters)

We have the volume of solution = 350 ml = 0.35 liters and the molarity = 3 m

Substituting in the equation, we get:
3 = number of moles / 0.35
number of moles = 3 x 0.35 = 1.05moles
3 0
2 years ago
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