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Lyrx [107]
4 years ago
5

Julio has $127 in his bank account. He gets $30 for his birthday. He also has a part-time job that pays $9 per hour. How many ho

urs will he need to work to have $220 in his bank account?
Mathematics
2 answers:
Klio2033 [76]4 years ago
7 0

Answer: he needs to work for 7 hours.

Step-by-step explanation:

Let x represent the number of hours that he need to work to have $220 in his bank account.

Julio has $127 in his bank account. He gets $30 for his birthday. Since the total amount he wants to have in his bank account is 220, it means that the remaining amount he needs to save is

220 - (127 + 30) = 63

He also has a part-time job that pays $9 per hour. It means that the amount that he would earn if he works for 9 hours is 9x. Therefore,

9x = 63

x = 63/9

x = 7

RideAnS [48]4 years ago
4 0

Answer:

7 hours

Step-by-step explanation:

127+30+9x=220

157+9x=220

9x=63

x=7

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50 % probability that the hat is blue.

Step-by-step explanation:

3 blue and 3 black = 6 total tickets

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3 years ago
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7 0
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Read 2 more answers
A mechanic makes $350 /week. If 20% of his income is deducted for taxes, how muchd id the mechanic bring home as pay?
klemol [59]

Answer:

$280

Step-by-step explanation:

Step one

Given data

A mechanic makes $350 /week

20% of his income is deducted for taxes

Required

the mechanic's take-home pay for the week

Step two:

let us find 20% of $350

=20/100*350

= 0.2*350

=$70

Therefore the take-home pay is

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= $280

8 0
3 years ago
What is the value of x?
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The bisector of an angle of a triangle divides the opposite side into segments that are proportional to the adjacent sides
VT/TK = VY/YK
95.2/168 = 34/YK
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3 years ago
In circle P, if the radius is 3 cm, what is the length of arc AD?
umka21 [38]

Hello there.

We have for a circle that:

\ell=\alpha r

Where:

\ell is the measure of the arc

\alpha is the measure of the angle (radians)

r is the radius of the circle


In our case, we have \alpha = 120^\circ = \dfrac{120}{180}\pi = \frac23\pi ~rad

We have r = 3 cm, then:

\ell = (\frac23\pi )(3\ cm)\\ \\ \boxed{\ell = 2\pi~cm}

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