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3 years ago

11

A cookie recipe for three dozen Caramel peanut butter bars uses 14oz of caramel. How much caramel (to the nearest ounce) should

be used to make 120 bars for a cookie exchange

1 answer:

tia_tia [17]3 years ago

4 0

140oz I believe because you just do 14oz times 10 because one dozen is 12 and 12 times 10 is 120.

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Mr. K has 112 feet of fencing to enclose a new garden. What is the maximum area of the garden that he can enclose?

musickatia [10]

Answer:

759 square foot garden

Step-by-step explanation:

L= length

W= Width

Perimeter = 2(L + W)

112 = 2(L + W)

divide both sides by 2 and you get

56 = L + W

L=33

W=23

6 0

2 years ago

Read 2 more answers

Whatwould u times by 9 to get 99?

Aleonysh [2.5K]

The answer would be 11.

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3 years ago

In a simple random sample of 14001400 young people, 9090% had earned a high school diploma. Complete parts a through d below.

ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has increased.

Step-by-step explanation:

Let <em>p</em> = proportion of young people who had earned a high school diploma.

A sample of <em>n</em> = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

$\hat p=0.90$

(a)

The standard error for the estimate of the percentage of all young people who earned a high school diploma is given by:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Compute the standard error value as follows:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=\sqrt{\frac{0.90(1-0.90)}{1400}}\\$

$=0.008$

Thus, the standard error for the estimate of the percentage of all young people who earned a high school diploma is 0.0080.

(b)

The margin of error for (1 - <em>α</em>)% confidence interval for population proportion is:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

Compute the critical value of <em>z</em> for 95% confidence level as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

$=1.96\times 0.0080\\=0.01568\\\approx1.6\%$

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

$CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)$

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has increased, the hypothesis is defined as:

<em>H₀</em>: The percentage of young people who earn high school diplomas has not increased, i.e. <em>p</em> = 0.80.

<em>Hₐ</em>: The percentage of young people who earn high school diplomas has not increased, i.e. <em>p</em> > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of <em>p</em>, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has increased.

8 0

3 years ago

Melanie invested $9,800 in an account paying an interest rate of 4.5 compounded quarterly. Amelia invested $9,800 in an account

Zolol [24]

Answer:

$13,082.60 more

Step-by-step explanation:

Melanie:

$A=P(1+\frac{r}{n})^(20)\\ A=9800(1+\frac{.045}{4})^(20)\\A=$12,257.36$

Amelia:

$A=Pe^(rt)\\A=9800e^(.0475*20)\\A=$25,339.95$

Amelia-Melanie= $13,082.60

6 0

2 years ago

1/2 (2n + 6) <br> simply the answer and show work

Evgesh-ka [11]

Answer:

The answer is n + 3.

Step-by-step explanation:

1) Simplify.

$\frac{2n + 6}{2}$

2) Factor out the common term 2.

$\frac{2( n+ 3)}{2}$

3) Cancle 2.

$n + 3$

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7 0

2 years ago