The answer is 0.690129 hope this helps:)
Answer:
No.
Step-by-step explanation:
The function is any equivalence relation in which there is only one output for every input. This means that the domain must be exhausted in order to gain all the elements of the range and each element of domain gets mapped to only one of the elements of the range. Vertical line test is used to determine whether a graph is a function or not. This test requires that vertical lines parallel to y-axis and including y-axis be drawn on the graph to see that each vertical line intersects the graph only once. This must be true for all the elements of the domain. Therefore, vertical line test requires to draw numerous vertical lines other than the y-axis since the definition of the function requires that. In short, mathematically, there will be a need for infinite number of vertical lines to perform the test. Therefore, Shayla is not applying the vertical line test correctly!!!

Step-by-step explanation:

Take
as common. Then,

Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS =
= 57.5°
Now, tan(57.5°) = 
⇒ 1.5697 = 
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) = 
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = (
) × (ST)
= (
) × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²