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zhannawk [14.2K]
3 years ago
5

What are the approximate solutions of 4x^2 + 3 = -12x to the nearest hundredth

Mathematics
2 answers:
iVinArrow [24]3 years ago
4 0
Approximate solutions are

X subset 2 is approximately equal to -2.72

X subset 1 is approximately equal to -0.28
shutvik [7]3 years ago
4 0

Hello from MrBillDoesMath!

Answer:    -.28 and   -2.72

Discussion:

This is a quadratic equation (where a = 4, b +12, and c = 3 using the standard notation involved in the solution)

4x^2 + 3= -12x  =>   (given). Add 12x to both sides

4x^2 + 12x + 3 = 0.


From the quadratic formula:

x =   ( -12 +\- sqrt ( 12^2 - 4(4)(3) )    )/ (2 * 4)

x =   ( -12 +\- sqrt (144 -48))/ (2 * 4)      

x =  ( -12 +\- sqrt (96))  / (2 * 4)    

x = ( -12 +\- sqrt(16*6) ) / (2 * 4)


The "+" solution,    x = -12/8  + ( 4 /8)sqrt(6) =  -3/2 + 1/2 (sqrt(6)) =  -.28

The "-" solution     x = -12/8  -  ( 4 /8)sqrt(6)  =  -3/2 - 1/2 (sqrt(6)) = -2.72


Regards,

MrB

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