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dexar [7]
3 years ago
5

What is one drawback for using pen tests and red teams to find security issues?

Mathematics
1 answer:
Nonamiya [84]3 years ago
7 0
<span>One of the drawback for using pen tests and red teams in order to find security issues is that is far more expensive to issue bug repairs after the soft ware product is finished and has been released. Prior to its release it is much cheaper to fix.</span>
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Who can help with this
vagabundo [1.1K]

GiveN:

  • ABCD is a parallelogram.
  • AC and BD are the diagonals.
  • DE = 28 units

To FinD:

  • Value of x in length of BE?

Step-wise-Step Explanation:

We know that,

In any parallelogram, the diagonals (lines linking opposite corners) bisect each other. Then, AE = EC for diagonal AC and BE = DE for diagonal BD.

⇒ BE = DE

⇒ x - 4 = 28 units

⇒ x = 32 units

Hence, The required value of x here is <u>3</u><u>2</u><u> </u><u>units</u><u>.</u>

7 0
2 years ago
An item cost $320 before tax and sales tax is $9.60 fine the sales tax rate. what is the answer as a percentage?
mario62 [17]

Answer:

329.6 $

Step-by-step explanation:

320 + 9.60 = 329.6

Hopefully this helps you :)

7 0
3 years ago
Construct a​ 95% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A random sam
aniked [119]

Given Information:  

Number of lithium batteries = n = 16

Mean life of lithium batteries = μ = 645 hours

Standard deviation of lithium batteries = σ = 31 hours

Confidence level = 95%  

Required Information:  

Confidence Interval = ?

Answer:  

CI = 628.5 \: to \: 661.5 \: hours

Step-by-step explanation:  

The confidence interval is given by

CI = \mu \pm t_{\alpha/2} (\frac{\sigma}{\sqrt{n}})

Where μ is the mean life of lithium batteries, σ is the standard deviation, n is number of lithium batteries selected, and t is the critical value from the t-table with significance level of

tα/2 = (1 - 0.95) = 0.05/2 = 0.025

and the degree of freedom is

DoF = n - 1 = 16 - 1 = 15

The critical value (tα/2) at 15 DoF is equal to 2.131 (from the t-table)

CI = 645 \pm 2.131(\frac{31}{\sqrt{16}})

CI = 645 \pm 2.131(7.75})

CI = 645 \pm 16.515

CI = 645 - 16.515 \: and \: 645 + 16.515

CI = 628.5 \: to \: 661.5 \: hours

Therefore, the 95% confidence interval is 628.5 to 661.5 hours

What does it mean?

It means that we are 95% confident that the mean life of 16 lithium batteries is within the interval of (628.5 to 661.5 hours)

6 0
3 years ago
Sarah had invested $800 in a savings account that paid 4.2% interest compounded annually. How much money was in the account afte
schepotkina [342]

Answer:  $943.11

<u>Step-by-step explanation:</u>

Compound Interest formula is:   A=P(1+r)^t     where

  • A is the Accrued amount (total earned)
  • P is the Principal (amount initially invested)
  • r is the interest Rate (convert percent to a decimal)
  • t is the Time (number of years)

It is given that; P = 800    r = 4.2% (0.042)       t = 4

A = 800(1 + 0.042)⁴

A = 800(1.042)⁴

A = 943.106   →   A = 943.11 (rounded to the nearest penny)

Sarah invested $800 for four years at an interest rate of 4.2% and accrued $943.11

5 0
3 years ago
Solve for W: P=2L + 2W<br><br>A. W=P-L<br>B. W= 1/2P - L<br>C. W= 1/2 P + L<br>D. W= 2P - L​
svetlana [45]

Answer:

B

Step-by-step explanation:

P=2L+2W

P-2L=2W (Subtract 2L from both sides of the equation)

2W=P-2L (Symmetric Property of Equality)

W=\frac{P-2L}{2} (Divide both sides of the equation by 2)

W=\frac{P}{2} -\frac{2L}{2} ("Split" the fractions)

W=\frac{1}{2}P-L (Simplify)

Hope this helps!

4 0
2 years ago
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