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4 years ago

What is one drawback for using pen tests and red teams to find security issues?

1 answer:

7 0

One of the drawback for using pen tests and red teams in order to find security issues is that is far more expensive to issue bug repairs after the soft ware product is finished and has been released. Prior to its release it is much cheaper to fix.

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A triangle has angles measuring 10 degrees, 40 degrees and 130 degrees with side lengths of 23 cm, 84 cm and 100 cm. Classify th

AnnyKZ [126]

Answer:

The correct answer is D. obtuse scalene

Step-by-step explanation:

1. Let's recall that a equilateral triangle has its three sides of the same length. An equilateral triangle is always equiangular. This is not our given triangle.

2. Let's recall that an isosceles triangle has two sides of the same length. This is not our given triangle.

3. Finally, let's recall that in a scalene triangle, none of the sides are the same length. And if one of the given angles is greater than a right angle, measures more than 90 degrees, it is an obtuse triangle. This is our given triangle.

The correct answer is D. obtuse scalene.

8 0

4 years ago

Tanθ<0 and (tanθ)(cscθ)>0

OleMash [197]

Que? Que es oofff what

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3 years ago

- Use the functions f(x) = 4x + 3 and g(x) = 2x2 + 2 to answer parts (a)-(c).

mario62 [17]

9514 1404 393

Answer:

a) f(x)

b) g(x)

c) for all values of x > 1, g(x) has a greater rate of change

Step-by-step explanation:

a) The rate of change of f(x) is the x-coefficient: 4. The average rate of change of g(x) on an interval can be found by dividing the change by the interval width. Here, the width of the interval of interest is 1-0 = 1, so the average rate of change is g(1) -g(0) = 4-2 = 2.

On the interval [0, 1], f(x) has the greater rate of change.

b) The interval [2, 3] also has a width of 1, so the rate of change of g(x) on that interval is g(3) -g(2) = 20 -10 = 10. This value is greater than 4, so ...

on the interval [2, 3], g(x) has the greater rate of change.

c) Part (b) demonstrates that g(x) will have a greater rate of change on some intervals. In fact, for any interval whose center is greater than x=1, g(x) will have a greater rate of change than f(x).

_____

In calculus terms, the rate of change of g(x) is g'(x) = 4x. This will be greater than 4 for any x > 1. The graph shows the rate of change is 4 at x=1, and is higher for x > 1. The average rate of change will be greater than 4 on any interval whose center is greater than x=1.

We can figure the average rate of change on the interval [a, b] as ...

m = (g(b) -g(a))/(b -a)

m = ((2b² +2) -(2a² +2))/(b -a) = 2(b² -a²)/(b-a) = 2(b+a)

For the average rate of change to exceed 4, the sum of the ends of the interval must exceed 2, which is to say the midpoint must exceed 1.

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3 years ago

A diver begins at 150 feet below sea level, descends at a steady rate of 5 feet per minute for 3.5 minutes, and then ascends 122

marusya05 [52]

Start at -150, then add 3(-5), then add 122.2. -150 + 3(-5) + 122.2 = -45.3

3 0

4 years ago

Read 2 more answers

The perimeter of a square must be greater than 102 inches but less than 138 inches. Find the range of possible side lengths that

liberstina [14]

Answer:

s ∈ (25.5,34.5)

''s'' is in inches unit

s ∈ IR

Step-by-step explanation:

We know that the perimeter of a square is $P=4s$

Where P is the perimeter and s is the length of a side.

We want the perimeter to be greater than 102 inches but less than 138 inches.

We can write :

102 inches < P < 138 inches

If we replace P = 4s in the expression :

102 inches < 4s < 138 inches

Dividing by ''4''

25.5 inches < s < 34.5 inches

If we want the perimeter to be greater than 102 inches but less than 138 inches the length of a side must be greater than 25.5 inches but less than 34.5 inches.

Writing this in interval notation

s ∈ (25.5,34.5)

s ∈ IR

4 0

3 years ago