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never [62]
2 years ago
14

Sam took his family to the zoo. An adult's ticket is two times the cost of a child's ticket. The total cost for two adults' tick

ets and three children's tickets was $28. How much do the tickets cost? A. Child's ticket = $5.60, adult's ticket = $11.20 B. Child's ticket = $2, adult's ticket = $4 C. Child's ticket = $4, adult's ticket = $8 D. Child's ticket = $7, adult's ticket = $14 \
Mathematics
2 answers:
givi [52]2 years ago
8 0
Is c the reason is 4x3=12 8x2=16 12+16=28
aleksklad [387]2 years ago
4 0
2a + 3c = 28
a = 2c

2(2c) + 3c = 28
4c + 3c = 28
7c = 28
c = 28/7
c = 4 <== childs ticket

a = 2c
a = 2(4)
a = 8 <== adults ticket
You might be interested in
How do you solve 39 equal to 1 3/10b
elena-s [515]
If 39 = (1 3/10)b, we could simplify this by writing 39 - (13/10)b.

Solve this for b by mult. both terms by (10/13):

(10*39)
----------- = (10/13)(13/10)b.  Then b = 30 (answer)
      13
5 0
2 years ago
15 points!!!
ankoles [38]

Answer:

Step-by-step explanation:

4/15×6/14= 0.1142

4 0
3 years ago
Use rhombus TQRS below for questions<br> what is the value of x?<br> what is the value of y?
sladkih [1.3K]

The value of x is 1.

The value of y is 4.

Solution:

Given TQRS is a rhombus.

<u>Property of rhombus: </u>

Diagonals bisect each other.

In diagonal TR

⇒ 3x + 2 = y + 1  

⇒ 3x – y = –1 – – – – (1)

In diagonal QS

⇒ x + 3 = y

⇒ x – y = –3 – – – – (2)

Solve (1) and (2) by subtracting

⇒ 3x – y – (x – y) = –1 – (–3)

⇒ 3x – y – x + y = –1 + 3

⇒ 2x = 2

⇒ x = 1

Substitute x = 1 in equation (2), we get

⇒ 1 – y = –3

⇒ –y = –3 – 1

⇒ –y = –4

⇒ y = 4

The value of x is 1.

The value of y is 4.

6 0
3 years ago
Use the table below. Find the total cost of 1 salad, 3 sandwiches, and 2 drinks. Use mental math.
zvonat [6]

Answer:

$11.5

Step-by-step explanation:

Add all of them together

8 0
3 years ago
PLEASE HURRY!! <br> simplify completely<br> show all work for full credit
Irina18 [472]

Answer:

4x^{3}

Step-by-step explanation:

<u>Given:</u>

(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}

<u>Apply exponent rule of distribution:</u>

\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}

<u>Simplify the numerator:</u>

\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}

<u>Simplify the denominator:</u>

\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}

<u>Simplify:</u>

4x^{3}

-> To explain this party since it is a bigger jump, 3^{\frac{1}{3}}x is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have x^{3} leftover too.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0
2 years ago
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