Answer:
22
Step-by-step explanation:
gcf 56, 120 = 8, 56/8=7, 120/8=15, 7+15=22. 22
One thing to pay close attention to is that, AB is a segment whose length is 12 cm, now we're not referring to the arcAB, but to the straight-line going from A to B, the segment AB, as you can see in the picture below in green.
now, the segments OA and OB are radius of the circle and therefore twins, and since they're twin sides, they make up twin angles on the other end, the green end.
if those angles at A and B are twins, the only possible values for them is 60°, what the dickens does all that mean?
well, it means the triangle AOB is an equilateral triangle, and if AB is 12, then OA and OB are also twelve, thus we know the radius of the circle is 12.

now, that is the circumference of that circle, and since we only need to know what arcAB is, and since arcAB is 1/6 of the circle, then 1/6 of that circumference is 24π/6.
Answer:
The approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357
Step-by-step explanation:
For a sample of 10 sqaured centimeters of dust, the total amount of asbestos particles has a Poisson distribution with a mean of 1000/1 * 10 = 10000.
We will approximate this probability to a normal distribution. The variance is also 10000 (because it is poisson), therefore the standard deviation is √10000 = 100. Lets call X the distribution, and W its standarization, given by

We have

Where
is the cummulative distribution function of a standard normal distribution. The values of
are well known and they can be found in the attached file.
We conclude that the approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357.
Hi there!
The answer to this question is A - multiply by 1/2. This is because multiplying by 1/2 does not get rid of the 1/2 on that side, which is what we want to do.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer: 6
<u>Step-by-step explanation:</u>
NOTE: log₆6 = 1
log₆6 + log₆(x - 5) = log₆6
1 + log₆(x - 5) = 1
log₆(x - 5) = 0
x - 5 = 6⁰
x - 5 = 1
x = 6