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3 years ago

10

What is 1.8399 rounded to the nearest tenth

2 answers:

victus00 [196]3 years ago

5 0

Answer:

1.8400

Step-by-step explanation:

Masteriza [31]3 years ago

3 0

1.84

explanation : the 9 rounds it to a 4

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What type of problems can always be solved using the law of cosines or sines?

laila [671]

Anytime you have a triangle (right triangles are preferred) where at least 2 angle measures and 1 side is known. Or, at least two sides and 1 angle measure.

OR..... 3 sides or three angles are known. So, sines or cosines could be used at almost anytime to find the sides and angles of a triangle!

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%204%7D%7B3%7D%20%20%3D%206" id="TexFormula1" title=" \frac{x + 4}{3} = 6

Gwar [14]

Multiply both sides by 3 to cancel out the 3 in the denominator of the left side of the equal sign. You get:

x + 4 = 18

Now subtract 4 from both sides to get variables one side, constants on the other.

x = 18 - 4
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Your answer is x = 14

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4 years ago

PLEASE HELP FOR THIS QN

lilavasa [31]

Answer:

$5^8$

Step-by-step explanation:

$5^{2^{3}}$

$5^{2 \times 2 \times 2}$

$5^8$

$=390625$

8 0

4 years ago

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

b) The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

3 0

4 years ago

The straight line ax+by=1passes through the points (1,4)and (3,1).Find the values of a and b?

Molodets [167]

Answer:

a= 3/11

b = 2/11

Step-by-step explanation:

a(1) + b(4) = 1

a + 4b = 1

a(3) + b(1) = 1

3a + b = 1

b = 1-3a

a + 4(1-3a) = 1

a+ 4-12a = 1

-11a = -3

a = 3/11

b = 1-3(3/11)

b= 2/11

3 0

3 years ago

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