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STALIN [3.7K]
3 years ago
11

What type of problems can always be solved using the law of cosines or sines?

Mathematics
1 answer:
laila [671]3 years ago
4 0
Anytime you have a triangle (right triangles are preferred) where at least 2 angle measures and 1 side is known. Or, at least two sides and 1 angle measure. 

OR..... 3 sides or three angles are known. So, sines or cosines could be used at almost anytime to find the sides and angles of a triangle!
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How to use the prime factorization and the distributive property to express the sum of 2 whole numbers as a product
likoan [24]

10 = 2x5  

12= 2x2x3

use the factor tree for both , hope this helps


4 0
3 years ago
ASAP PLEASE please please
Aleksandr [31]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \cfrac{1}{b}  + 10 =  \cfrac{9}{b}  + 7

\qquad \sf  \dashrightarrow \:  \cfrac{9}{b}  -   \cfrac{1}{b} =  10 -   7

\qquad \sf  \dashrightarrow \:  \cfrac{8}{b}   =  3

\qquad \sf  \dashrightarrow \: b =  \cfrac{8}{3}

5 0
2 years ago
Read 2 more answers
EMERGENCY I HOPE SOMEONE HELPS ME <br> THANKS
kotykmax [81]
0.28 is the answer unless u put it like 28/100
4 0
3 years ago
How do you get to the point (-3.4)? *
kaheart [24]

Answer:

3 down, 4 up

Step-by-step explanation:

-3 is the X line, which starts on 0, if you subtract 3, or add -3, you would have to go down, 3 down. 4 is on the Y line, so you add, go left to add on the Y line, 4 up.

Always start with you X coordinate. Here is a tip to help you (X, Y)

7 0
3 years ago
A room has an area of 60 square meters and a perimeter of 32 meters what are the length and width of the room
kupik [55]
We can solve this by looking at pairs that equal 60.
6 and 10 get to 60 when multiplied. Let's see  if it fits in as a perimeter.
12+20=32
So the width and length of the room is 6 meters and 10 meters.
5 0
3 years ago
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