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balu736 [363]
3 years ago
14

A new car is purchased for 23900 dollars. The value of the car depreciates at 9.75% per year. To the nearest year, how long will

it be until the value of the car is 7700 dollars?
Mathematics
1 answer:
inna [77]3 years ago
6 0

Answer:

11 years

Step-by-step explanation:

we know that

The  formula to calculate the depreciated value  is equal to  

V=P(1-r)^{x}  

where  

V is the depreciated value  

P is the original value  

r is the rate of depreciation  in decimal  

x  is Number of Time Periods  

in this problem we have  

P=\$23,900\\r=9.75\%=0.0975\\x=?\\V=\$7,700

substitute in the formula

7,700=23,900(1-0.0975)^{x}  

(77/239)=(0.9025)^{x}  

Apply log both sides

log(77/239)=xlog(0.9025)  

x=log(77/239)/log(0.9025)  

x=11\ years

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Since none of the options make sense with 23, I assume it was a typo, and you meant 2/3.

Let l,w and h be the length, width and height of the original prism, and l',w' and h' be the length, width and height of the new prism. We are given

l' = l\times \cfrac{2}{3},\quad w' = w\times \cfrac{2}{3},\quad h' = h\times \cfrac{2}{3}

Also, if we call V the original volume, and V' the volume of the new prism, we have

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Substitute the expressions for l', h' and w' in the formula for V':

V'=l'h'w' = l\times \cfrac{2}{3}\times w\times \cfrac{2}{3}\times h\times \cfrac{2}{3} = l\times h \times w \times \cfrac{2}{3}\times\cfrac{2}{3}\times\cfrac{2}{3} = V \times \left(\cfrac{2}{3}\right)^3 = V\times\cfrac{8}{27}

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3 years ago
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help me please can someone please help i beg you. i have to say why this is wrong and solve this correctly. i beg you please
e-lub [12.9K]

Answer:

The person solving the problem first subtracted 6 from 15. Since the cube root is next to the six, the problem should be read as 15-6(\sqrt[3]{\frac{-1000}{27} } ) rather than (15-6)(\sqrt[3]{\frac{-1000}{27} } ).

  • To solve it correctly, first find the cube root of -1000/27: <u>-10/3</u>
  • Next, multiply by 6: -20
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please lmk if anything is wrong with my answer, hope this helps :)

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