Answer:
31.5 in
Step-by-step explanation:
- Volume of a hemisphere = (2/3)
r³
(where r is the radius)
- Volume of a cylinder =
r²h
(where r is the radius and h is the height)
- radius r = (1/2) diameter
First, find the volume of the scoop using the volume of a hemisphere formula with r = 21:
Volume = (2/3)
x 21³ = 6174
in³
Now equate the found volume of the scoop to the equation of the volume of a cylinder with r = 14, and solve for h:
14²h = 6174
196
h = 6174
Divide both sides by
: 196h = 6174
Divide both sides by 196: h = 31.5
Therefore, the height of the molten steel in the storage tank is 31.5 in
Answer:
Proved Below
Step-by-step explanation:

Hence, Proved that
is equivalent to
.
Answer:
y≤ -1/4 - 7x/8
Step-by-step explanation:
Mathrie 134x3= 402 ship names are my specialty:)
Answer:
x=12
Step-by-step explanation:
move the 3 to the other side to get x by itself.
check: 12 + 3 = 15