This has to do with ratio's.
MQ : QN = 2 : 5
MQ : QN = LP : PN
2 : 5 = 3 : PN
That means PN = 15/2
The surface charge density:
S(igma) = Q / A
A = 1.6 * 10^(-2) * 1.6 * 10^(-2) = 2.56 * 10^(-4) m²
The electric field: E = S / E(psilon) o
E = 0.711 * 10^^(-9) / ( 2.56 * 10 ^(-4) * 8.85 * 10 ^(-12) ) =
= 0.3138 * 10 ^6 = 3.138 * 10^5 V/m
a ) Δ V = E d
Δ V = 3.138 * 10^5 V/m* 1.2 * 10^(-3) m = 376.56 V
b ) When d = 2.40 mm:
Δ V = 3.138 * 10^5 V/m * 2.40 *10^(-3) m = 753.12 V
Answer:
351.68 millimeters for the cylinder and 8 23/75 millimeters for the half circle.
Step-by-step explanation:
Volume Cylinder = 3.14(16)(7) = 351.68
Volume Half sphere = 2/3(3.14)(4) = 8 23/75
If you want both of them together just add up the two numbers.
