Jenny is tracking the monthly sales totals for her boutique. The given piecewise function represents the boutique's monthly sale
s, in dollars,
where x represents the number of months since Jenny began tracking the data.
0 < I<3
f(0) =
100.5 + 5,024
3 -12 + 53 +5,630, 6 (4,000(1.1)",
What were the boutique's monthly sales when Jenny first began tracking the data?
A
$4,000
В.
$5.324
C. $5,616
D. $4,400
where x represents the number of months since Jenny began tracking the data.
0 < I<3
f(0) =
100.5 + 5,024
3 -12 + 53 +5,630, 6 (4,000(1.1)",
What were the boutique's monthly sales when Jenny first began tracking the data?
A
$4,000
В.
$5.324
C. $5,616
D. $4,400
1 answer:
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<h2>Hello!</h2>
The graph is attached.
To graph a parabola we need to know the following:
- If the parabola is open upwards or downwards
- They axis intercepts (if they exist)
- The vertex position (point)
We are given the function:
Where,
For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.
Finding the axis interception points:
Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:
Using the quadratic equation:
So, at t=4.0615 the height of the softball will be 0.
Since we will work only with positive values of "x", since we are working with a function of time:
Let's start from "t" equals to 0 to "t" equals to 4.0615.
So, evaluating we have:
Finally, we can conclude that:
- The softball reach its maximum height at t equals to 2. (68 feet)
- The softball hits the ground at t equals to 4.0615 (0 feet)
- At t equals to 0, the height of the softball is equal to 4 feet.
See the attached image for the graphic.
Have a nice day!