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Answer:0.1446
Step-by-step explanation:
Let p be the population proportion of adults say that cloning of humans should be allowed.
As per given , the appropriate set of hypothesis would be :-
Since is left-tailed and sample size is large(n=1012) , so we perform left-tailed z-test.
Given : The test statistic for this test is -1.06.
P-value for left tailed test,
P(z<-1.06)=1-P(z<1.06) [∵P(Z<-z)=1-P(Z<z]
= (Using z-value table.)
Hence, the p-value for this test statistic= 0.1446