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netineya [11]
4 years ago
15

Adjacent, right angles are complementary. always, sometimes, or never

Mathematics
2 answers:
IgorLugansk [536]4 years ago
7 0
Adjacent right angles are Never complementary
DerKrebs [107]4 years ago
4 0
What you'll need to answer this question are the definitions of adjacent, right angle, and complementary. For the sake of this question, I'll give you those definitions:

- Two angles are <em>adjacent</em> when they lie next to each other across a line. Imagine you have two line segments forming an angle, and that that angle is cut in half by another line segment, forming two smaller angles. Each of those smaller angles is <em>adjacent</em> to the other.
- A <em>right </em>angle is an angle formed at the meeting point of two <em>perpendicular </em>lines. For an example of what it means to be perpendicular, think of the angles a plus sign forms at each of its corners - those lines are what are called perpendicular.
- <em>Complementary</em> angles are two angles which add up to a right angle.

With this knowledge, take a look at the question again. Is it possible for two <em>right angles</em> that are <em>next to each other</em> to add up to <em>another right angle?</em> Can <em>any </em>number greater than zero, when added to itself, ever <em>equal itself</em>?
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Please show work
Anit [1.1K]

(1)

since both equations express y in terms of x, equate the right sides

- 2x = - 4x + 10 ( subtract 4x from both sides )

2x = 10 ( divide both sides by 2 )

x = 5

substitute x = 5 into y = - 2x → y = - 10

solution is : (x, y ) → (5, - 10 )

(2)

equate the right sides of both equations

3x = 2x - 7 ( subtract 2x from both sides )

x = - 7

substitute x = - 7 into y = 3x → y = - 21

solution is : (x, y) → (- 7, - 21)

(3)

substitute y = - 8 into the other equation

- 8 = 6x + 22 ( subtract 22 from both sides )

- 30 = 6x ( divide both sides by 6 )

x = - 5

solution is : (x, y ) → (- 5, - 8 )



6 0
3 years ago
Solve for v.<br> 5v- 13=22
aliina [53]

Answer:

5(7)-13=22

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Given: Elmwood St. and Oak Dr. are the same distance. All intersections are perpendicular.
vlabodo [156]

Answer:

The above result is proved with the help of Pythagoras theorem and explained below.

Step-by-step explanation:

Given figure ABCD in which AD=BC and all angles intersect at right angle. Hence, the triangle formed inside ADC and ABC are right angled triangle.

In triangle ADC,

By applying Pythagoras theorem, we get

AC^{2}=AD^{2}+DC^{2}    →  (1)

In triangle ABC,

AC^{2}=AB^{2}+BC^{2}    →  (2)

Now, from eq (1) and (2)

Peach Tree Dr. is the same distance as Sycamore Ln.


AD^{2}+DC^{2} = AB^{2}+BC^{2}

⇒ DC^{2} = AB^{2}              (∵ AD=BC)

⇒ DC=AB                    (∵Distance can never negative)

Therefore, Peach Tree Dr. is the same distance as Sycamore Ln.


8 0
3 years ago
(35)8 + (25)6 help plz
jonny [76]

Answer:

430

Step-by-step explanation:

Use PEMDAS.

(35)8 + (25)6\\35*8= 280\\25*6= 150\\280 + 150=430

7 0
4 years ago
Write x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers. (1 point)
Brut [27]
X² - 6x + 7 = 0
x² - 6x = -7
x² - 6x + 9 = -7 + 9
(x-3)² = 2
7 0
3 years ago
Read 2 more answers
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