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2 years ago

120 books of the same size are packed in 5 boxes. How many such boxes are needed to pack 216 similar books?

Mathematics

1 answer:

monitta2 years ago

7 0

Answer:

lets find how many books are in each box

120/5=24

so 24 book in a box so lets divide for the 216 books

216/24=9

9 boxes

Hope This Helps!!!

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an employee adds 160 fluid ounces of chemical to a feature that holds 120,000 gallons of water. did the employee add yhe correct

Hitman42 [59]

We are given a volume of 160 fluid ounces of chemical which is added to a container that holds 120,000 gallons of water. Assuming that the chemical has the same density as water, we just need to convert 120,000 gallons to ounces.

A conversion factor is taken from literature, 1 gallon is equivalent to 128 fluid ounces. So 160 fluid ounces is only 1.25 gallons, thus occupying minimal space in the container. The employee could add more of the chemical in the container. He can actually add 15360000 fluid ounces in total.

5 0

3 years ago

A bag contains 7 blue, 4 yellow, 4 green, and 5 red marbles. Find the probability of choosing a green marble without looking. Ma

Naddik [55]

Answer:

1/4

Step-by-step explanation:

total balls=7+4+4+5=20

probability of green marble=?

green marbles are 5 so,

Probability=number of favourable outcomes / number of all possible outcomes

total outcomes=20

green ball chances=5

=5/20

=1/4

3 0

3 years ago

A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past

Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

Let $\mu$ = average miles for deluxe tires

So, Null Hypothesis, $H_0$ : $\mu \geq$ 50,000 miles {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, $H_A$ : $\mu$ < 50,000 miles {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is One-sample z test statistics as we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean lifespan = 46,500 miles

$\sigma$ = population standard deviation = 8000 miles

n = sample of tires = 28

So, test statistics = $\frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }$

= -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0

3 years ago

Let x be a positive integer. If (-3)ºx (-3)* = (-3)14, what is x?

Nezavi [6.7K]

Answer:

$-3^{\circ \:}x\left(-3\right)=\left(-3\right)\cdot \:14 : x = \frac{840}{180^{\circ \:}}$