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3 years ago

75 pts if you can awnser this

Mathematics

2 answers:

stellarik [79]3 years ago

7 0

Answer:

x = 4

Step-by-step explanation:

2.5x +6 = 3.25x +3

-2.5x -2.5x

6 = 0.75x +3

-3 -3

3 = 0.75x

divide by 0.75 both sides

4 = x

x = 4

kobusy [5.1K]3 years ago

5 0

Step-by-step explanation:

Madison gets an allowance of $6 every week. For every chore she does, her parents give her an extra $2.50 for that week. Daniel receives an allowance of $3 a week and gains $3.25 for every chore he does the same week. How many chores would have to be done by both of the children to earn the same amount of money?

2.5x + 6 = 3.25x + 3

Isolate the variable by:

subtracting 3 from both sides

2.5x + 3 = 3.25x

subtracting 2.5x from both sides

3 = 0.75x

divide 0.75 from both sides

4 = x

In terms of my example problem, the answer would be 4 chores

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andriy [413]

Answer:

9890

Step-by-step explanation

7×43×30+5×4×43=9890

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2 years ago

If the given figure is rotated 90 degrees counterclockwise around the origin, what are

Lisa [10]

Answer:

the answer is (-4,2)

hope this helps

7 0

3 years ago

At what values of x does f(x) = x^3 - 2x^2 -4x+1 satisfy the mean value theorwm on [0,1]

denis-greek [22]

Answer:

x=1/3

Step-by-step explanation:

A function f is given as

$f(x) = x^3-2x^2-4x+1$ in the interval [0,1]

This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)

Hence mean value theorem applies for f in the given interval

$f(1) = 1-2-4+1 = -4\\f(0) = 1$

The value

$\frac{f(1)-f(0)}{1-0} =\frac{-4-1}{1} =-5$

Find derivative for f

$f'(x) = 3x^2-4x-4$

Equate this to -5 to check mean value theorem

$3x^2-4x-4=-5\\3x^2-4x+1=0\\\\(x-1)(3x-1) =0\\x= 1/3 : x = 1$

We find that 1/3 lies inside the interval (0,1)

4 0

3 years ago

What is the slope and rate change?

jekas [21]

Slope is 3/2 rate of change is

7 0

3 years ago

2x+3y=1 and y=-2 - 9 solve using linear combination method. Please explain steps.

kaheart [24]

Answer:

$x=17$

Step-by-step explanation:

$2x+3y=1$

$y=-2-9$

In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value, $y$ . In this case, we need to isolate $y$ in the first equation so that both equations $=y$ .

$2x+3y=1$

$3y=-2x+1$

$\frac{3y}{3}=\frac{-2x+1}{3}$

$y=-\frac{2}{3}x+\frac{1}{3}$

With this, we now know that both $-2-9$ and $-\frac{2}{3}x+\frac{1}{3}$ are equal to $y$ , so we can set them equal to each other.

$y=-\frac{2}{3}x+\frac{1}{3}$

$y=-11$

$-\frac{2}{3}x+\frac{1}{3}=-11$

Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for $x$ .

$-\frac{2}{3}x+\frac{1}{3}=-11$

$-\frac{2}{3}x=-11-\frac{1}{3}$

$-\frac{2}{3}x =-\frac{33}{3}-\frac{1}{3}$

$-\frac{2}{3}x =-\frac{34}{3}$

$-\frac{2}{3}x(-\frac{3}{2})=-\frac{34}{3}(-\frac{3}{2})$

$x=\frac{102}{6}=17$

$x=17$

Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.

4 0

3 years ago