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Nutka1998 [239]

3 years ago

14

Multiple choose math question

1 answer:

guapka [62]3 years ago

5 0

B
( A P E X )................

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What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

6 0

3 years ago

Help! 15 Points, FRACTIONS.

Dafna11 [192]

Answer:

7/8 estimated would be about 1 and 6/11 is almost a half so it would be estimated 1/2 so 1 - 1/2 = 1/2

3 0

3 years ago

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Find the length of CA to the nearest tenth of a foot

hoa [83]

Answer:

CA ≈ 3.1 ft

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan40° = $\frac{opposite}{adjacent}$ = $\frac{BC}{CA}$ = $\frac{2.6}{CA}$ ( multiply both sides by CA )

CA × tan40° = 2.6 ( divide both sides by tan40° )

CA = $\frac{2.6}{tan40}$ ≈ 3.1 ft ( to the nearest tenth )

3 0

3 years ago

What is the value of the digit 8 in 686,293

e-lub [12.9K]

80,000 is the value

4 0

3 years ago

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Factor the expression using the GCF: 12x + 36 *

Rashid [163]

The answer fam is.........12(x + 3)

6 0

3 years ago