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nasty-shy [4]
3 years ago
5

If x-7=14, then what is the value of x-2

Mathematics
2 answers:
Semenov [28]3 years ago
8 0
If  x- 7 = 14 
 X = 21. 
21-2= 19
Volgvan3 years ago
4 0
If  x- 7 = 14 then X = 21. so 21-2= 19.      :)
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Roy worked for 2 hours and earned $12. how many hours must he work at the same rate to earn $36? hours worked 2 ? dollars earned
kotegsom [21]
2hr=$12
1hr=12/2= $6/hr
$36=1hr/$6= 6hr for $36
If he worked 3hr he would get (6*3)= $18
If he worked 4 hours he would get (6*4)= $24
I hope this answers your question
7 0
3 years ago
What is the x-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:5?
Marianna [84]

Answer:

Second option is correct. The x-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:5 is -2.

Step-by-step explanation:

From the given graph  it is noticed that the endpoints of the line segment JK are J(-6,-2) and K(8,-9).

The formula to find x intercept.

x=\frac{m}{m+n}(x_2-x_1)+x_1

The ratio is 2:5, therefore the value of m is 2 and the value of n is 5.

x=\frac{2}{2+5}(8-(-6))+(-6)

x=\frac{2}{7}(14)-6

x=4-6

x=-2

Therefore the x-coordinate is -2 and second option is correct.

6 0
3 years ago
Read 2 more answers
Can somebody help me please I need help
V125BC [204]
What do you need help with?
7 0
3 years ago
a team of 10 players is to be selected from a class of 6 girls and 7 boys. match each scenario to its probability
mars1129 [50]

Step-by-step explanation:

The selection of r objects out of n is done in

many ways.

The total number of selections 10 that we can make from 6+7=13 students is  

thus, the sample space of the experiment is 286

A.  

"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

P(all 6 girls chosen)=35/286=0.12

B.

"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is  

so the probability is 20/286=0.07

C.

"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.  

the probability is 105/286=0.367

since  case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.

"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in  

many ways,

so the probability is 126/286=0.44

Did this help??

8 0
3 years ago
How many minutes are there in 2 3/5
zzz [600]

in hours there would be 156 minutes


5 0
3 years ago
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