Answer:
i don't even know the answer to this stuff lol
Answer:
its B
Step-by-step explanation:
The answer to this question is 1, because the to lines intersect at point (3, 1).
I hope this helped!
Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Answer:
question 9
= –12
while question 11=, x= –72
Step-by-step explanation:
question 9=
u= –16+4= –12
question 11=
cross multiplication
x = -36 multiplied by 2 =
-72
I HOPE THIS HELPED IF WRONG IM SORRY
