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Nookie1986 [14]

3 years ago

13

Make this improper fraction a whole number 14/8

2 answers:

Ugo [173]3 years ago

4 0

The number is 1 3/4.

Nezavi [6.7K]3 years ago

3 0

Divide by 2 and you get 7/4

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PLEASE HELP !!!!! Find the surface area of a cone with radius of 7.9 cm and slant height of 3.7 cm, to the nearest square unit.

Anon25 [30]

For this case what you need to know is that the formula for the total surface area of a straight cone is
S.A = πrl + π r ^ 2
Substituting the values we have:
S.A = (3.14) * (7.9) * (3.7) + (3.14) * (7.9) ^ 2
S.A = 287.7496 cm ^ 2
Answer:
the surface area of a cone is
D) 288 cm ^ 2

3 0

4 years ago

Each of 4 tables at a party is set with a bowl of grapes. Each

andre [41]

Answer:

2.5

Step-by-step explanation:

youll have to multiply 4 times 5/8

8 0

3 years ago

Calculus 2 Master needed, show steps with partial fraction decomposition <img src="https://tex.z-dn.net/?f=%5Cint%283x%5E2-26x%2

Vladimir79 [104]

Answer:

-ln|x−5| + 2 ln(x²+4) + 3 tan⁻¹(x/2) + C

Step-by-step explanation:

The fraction will be split into a sum of two other fractions.

The first fraction will have a denominator of x − 5. The numerator will the a polynomial of one less order, in this case, a constant A.

The second fraction will have a denominator of x² + 4. The numerator will be Bx + C.

$\frac{3x^{2}-26x+26}{(x-5)(x^{2}+4)}=\frac{A}{x-5} +\frac{Bx+C}{x^{2}+4}$

Combine the two fractions back into one using the common denominator.

$\frac{A}{x-5} +\frac{Bx+C}{x^{2}+4}=\frac{A(x^{2}+4)+(Bx+C)(x-5)}{(x-5)(x^{2}+4)}$

This numerator will equal the original numerator.

$A(x^{2}+4)+(Bx+C)(x-5)=3x^{2}-26x+26\\Ax^{2}+4A+Bx^{2}-5Bx+Cx-5C=3x^{2}-26x+26\\(A+B)x^{2}+(C-5B)x+(4A-5C)=3x^{2}-26x+26$

Match the coefficients.

$A+B=3\\C-5B=-26\\4A-5C=26$

Solve the system of equations.

$A=-1\\B=4\\C=-6$

So we can rewrite the integral as:

$\int {(\frac{-1}{x-5}+\frac{4x-6}{x^{2}+4}) } \, dx$

Solving:

$\int {\frac{-1}{x-5}\, dx + \int {\frac{4x}{x^{2}+4}} \, dx - \int {\frac{6}{x^{2}+4} } \, dx$

$-\int {\frac{1}{x-5}\, dx + 2\int {\frac{2x}{x^{2}+4}} \, dx - 6\int {\frac{1}{x^{2}+4} } \, dx$

$-ln|x-5| + 2ln(x^{2}+4) - 6(\frac{1}{2} tan^{-1}(\frac{x}{2} )) + C$

$-ln|x-5| + 2ln(x^{2}+4) - 3 tan^{-1}(\frac{x}{2} ) + C$

5 0

3 years ago

Cruz is the editor of a magazine.

Nikitich [7]

Answer:

22

Step-by-step explanation:

20% * 40 = 20 / 100 * 40 = 800 / 100 = 8

1/4 * 40 = 40 / 4 = 10

So far we have use 8 + 10 = 18

There are 40 - 18 pages left

articles = 22

6 0

3 years ago

Simultaneous equations <br>5x + 3y= 31<br>2x + y = 12 <br><br>a. find for x<br>b. find for y

Anna007 [38]

Answer:

x=5

y=2

Step-by-step explanation:

5x + 3y= 31

-6x - 3y = -36 (multiple by -3)

-x=-5

x=5

2(5)+y=12 or 25 + 3y= 31

10+y=12 3y=6

y=2 y=2

8 0

3 years ago

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